Latest TCS Aptitude Question SOLUTION: 1!+2!+........+50!=?

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(#M40011013) TCS question Keep an EYE

1!+2!+........+50!=?

Asked In TCS manu (11 years ago)

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mano  (11 years ago)

this summation can be defined by reverse recurssion
if you want the sum of the factorials from 1 to n then start with
s(n) = n
and then
s(i) = i * ( 1 + s(i+1) )
and s(1) gives the summation
for example if n=4 we have
s(4)=4
s(3)=3*(4+1)=15
s(2)=2*(15+1)=32
s(1)=1*(28+1)=33
which agrees with
1!+2!+3!+4! = 1+2+6+24
using a computer program and using this recurssion method I get the sum as
31035053229546199656252032972759319953…

i dont think there is a mathematical formula for it.. but the following program works

public class A
{
public static void main(String[] args)
{
int answer = 1;
int sum = 0;
for (int i = 1; i

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