Latest TCS Aptitude Question SOLUTION: find the probability of the leap year choosen randomly will have 53 sundays?

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(#M40113152) TCS Numerical Ability question Keep an EYE

find the probability of the leap year choosen randomly will have 53 sundays?

Asked In TCS gowri (9 years ago)

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Abhimanyu kumar  (9 years ago)

since leap has 52 week and 2 odd days.
so 2 odd days may be as follows:-
sun mon
mon tue
tue wed
wed thr
thr fri
fri sat
sat sun
so total sample is 7
and 2 favorable sample that is sun mon and sat sun so
probality of a leap year choosen randomly wil have 53 sundays is 2/7
Ans :-2/7

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Surit Datta  (9 years ago)

Our sample space is S : {Monday-Tuesday, Tuesday-Wednesday, Wednesday-Thursday,..., Sunday-Monday}
Number of elements in S = n(S) = 7
What we want is a set A (say) that comprises of the elements Saturday-Sunday and Sunday-Monday i.e. A : {Saturday-Sunday, Sunday-Monday}
Number of elements in set A = n(A) = 2
By definition, probability of occurrence of A = n(A)/n(S) = 2/7
Therefore, probability that a leap year has 53 Sundays is 2/7.
(Note that this is true for any day of the week, not just Sunday)

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P.Surendra  (9 years ago)

2/7 because Sunday is repeated in twice

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durga  (9 years ago)

2/7 is ans

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elamaran  (9 years ago)

2/7....................................................................................................................................................................

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Puja  (9 years ago)

Pls Explain

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