Latest Capgemini Aptitude Question SOLUTION: In a race from pt. X to pt Y and back, Jack averages 30miles/hr to pt Y and 10 miles/hr back to pr X.Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at

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(#M40011445) CAPGEMINI Numerical Ability question time and work Keep an EYE

In a race from pt. X to pt Y and back, Jack averages 30miles/hr to pt Y and 10 miles/hr back
to pr X.Sandy averages 20 miles/hr in both directions. If Jack and Sandy start race at same tym,
who’ll finish 1st

Asked In Capgemini poompavai (11 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (11)   (3) Submit Your Solution Time Distance and Speed

Read Solution (5) :

vignesh raghupathi  (11 years ago)

The Average speed of Jack is 15mph by 2xy/x+y.
and sandy is 20miles/hr...
by comparing both speed sandy will reach first..

Is this solution Helpfull? Yes (40) | No (3)  

Madhumalati Sarkar  (11 years ago)

jack's average speed will be (30+10)/2=20 miles/hr
since he covered same distance both times
so, both will reach same time at the finish

Is this solution Helpfull? Yes | No (27)  

Sushma Kiran  (7 years ago)

at same time since distance and time is same
avg=s1+s2/2

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NIKHIL  (7 years ago)

let D=60Km
jack avg time= 60/30+60/10=2+6=8
sandy avg time=60/20+60+20=3+3=6
thus, sandy will finish first.

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Prachal Augustine  (5 years ago)

3 answers · Geography
Best Answer
They will tie. 30 one way and 10 the other is an average of 20, same as Sandy.
trea0766 · 1 decade ago
Comment 1 5
Answers
To solve this we can just make a "guess" which will make this a little simpler...we can just "guess" that the distance is 1 mile from X to Y...this way we will be working with easier numbers.
First Jack
X->Y
If the distance is 1 mile and Jack can run for 30 miles in 1 hour we can see that it would take jack 2 minutes to get there [1 mile*(1 hour/30 miles)*(60 minutes/1hour)] = 2 minutes.
Y->X
If he can run 10 mph on the way back then it would be [1 mile*(1 hour/10 miles)*(60 minutes/1hour)] = 6 minutes.
The total time taken it is 8 minutes.

Sandy
If she can run 20 mph on the way back then it would be [1 mile*(1 hour/20 miles)*(60 minutes/1hour)] = 3 minutes.
and she does that twice so it takes her 6 minutes.

It takes Jack 8 minutes and it takes Sandy 6 minutes...so Sandy finishes first.

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