Latest TCS Aptitude Question SOLUTION: two identical circles intersect so that their centres and the points at which they intersect form a square of side 1 cm the area in sq .cm of the portion that is commin to the two

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two identical circles intersect so that their centres and the points at which they intersect form a square of side 1 cm the area in sq .cm of the portion that is commin to the two circles is

pi/2-1
4
root 2
root 5

A semicircle is drawn with AB as its diameter from c a point on AB a line perpendicluar to AB is meeting the circumference of thr semicirlce at D Given that AC =2 cm and cd=6 cm the are of th semicircle in sq.cm will be
50pi
55
31
82
what is the distance in cm between two parallel chords of lenghts 32 cm and 24 cm in a circles of radius 20 cm
4 28
3 21
2 14
1 7

Two full tanks one shaped like a cylinder and the other like a cone contain liquid fuel the cylindrical held 500 litres more than the conical tank After 200 litres of fuel is pumped out from each tank the cylindrical tank now contains twice the amount of fuel in the conical tank how many liters
of fuel did the cylindrical tank have when it was full
1200
1100
700
1000
find the number of zeroes in the experssion 15*32*25*22*4075*98*112*125
9
14
7
12

the price of a commodity (in rupees per kilogram is 100+0.1n, on the nth day of 2007 (n=1,2,,,,100),
and then remains constant,on the other hand the price of another commodity in rupees per kilogram is 89+0.15n ,on the nth day oof 2007(n=1,2,...,365)
on the which date in 2007 will the prices of the tthese two commodities be equal?
may 20
may 21
april 10
april 11

I how many ways can 7 different objects be divided among 3 persons so that either one or two of them do not get any objects?
381
84
36
180
in how manys ways can the letters of english alphabet be arranged so that there are seven letters between the Aand B and no letter is repeated?
36*24!
18*24!
24P7*2*18!
24P7*3*18!
In this question x^y means X raised to the power Y how many integer x satisfy the equation (x^2-x-1)^(x+2)=1
4
2
3
none
Three distinct single dogit numbers A,B and C Geometric Progession I abs(x) for real x is the absolute of x(x if x is positive or zero and -x if x x is negative ) then
the number of different possible values of abs(A+B-C) is
5
4
3
6
two vechicles A and B leaves from city Y to city A overtakes B at 10.30am and reaches city X at 12.00pm
It waits for 2hrs and returns to city Y.on its way it meets B at 3.00pm and reaches city Y at 5.00pm .B reaches city x waits for 1 hr
and returns to city Y after how amny hour will B reach ciy Y from the time A overtook him for the first
time?
41.5 hrs
50 hrs
37.5 hrs.
49.5hrs

two identical circles intersect so that their centres and the points at which they intersect from a square of side
1 cm the area in sq.cm of the portion that is common to the circles is
root 5
root 2-1
pi/2-1
4
what is the distance in cm between in cm two parallel chords of lenghts 32 cm and 24 cm in a circle
of radius 20cm
4 or28
1or7
2 or14
3 or21

Two consective numbers are removed from the progression 1,2,3, n the arithmetic mean of the remaining number is 26 1/1 the values of n
n is
81
60
50

Asked In TCS saranya (9 years ago)

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umabhargavi  (9 years ago)

answer to the last question is 50
Let numbers removed by x and x+1
1+2+3+...n = n(n+1)/2
Mean = (n+1)/2

1+2+3... -x -(x+1) = n(n+1)/2 - x - (x+1)
Mean = (n(n+1)/2 - x - x - 1 )/ n-2 = 105/4
n^2 + n - 4x - 2 = (n-2)105/2
n^2 + n - 4x - 2 - 52.5n +105 = 0
n^2 -51.5n +103-4x=0
n=[ 51.5 +- root(51.5^2 +16x - 412) ]/ 2
now this root should give a value like xyz.5 so that it can combine with 51.5 and make an integer
here, hit and trial comes into play.
51.5^2 - 412 = 2,240.25
2240.25 + 16x should be a perfect square
x=1 make this a square of 47.5
n = 2 and n = 99/2(not integer)
n=2 is not possible. neither is n=99/2
so keep looking for more x
square of 48.5 - 2240.25 gives 112 which is 7*16
so put x=7
n = 1.5 and n=50
n=50 is good enough
so 1 possible answer is
n=50, number removed 7 and 8

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Deboshree Dey  (9 years ago)

the ans of second question is a)50 pi
if we take it as a whole circle then if AB is diameter and CD perpendiculer to it then let imagine CD is extended and meeting the circumference at E thus CD=CE=6cm
there is a the theorem that " if two chord let AB and CD intersect each other at O then AO*OB=CO*OD"
thus with this we can calculate CB=(CD*CE)/AC = 18cm
the total diameter is 18+2=20 cm then redius=10 cm
the area of semi circle is pi*100/2=50 pi

Is this solution Helpfull? Yes (2) | No   

Deboshree Dey  (9 years ago)

for third question ans is a)28
4th question ans is a)1200
5th question ans is c)7

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