Latest TCS Aptitude Question SOLUTION: An Old man and a Young man are working together in an office and staying together in a near by apartment. The Old Man takes 30 minutes and the Young 20 minutes to walk from apartme

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(#M40011589) TCS Numerical Ability question An Old man and a Young man are working together in an office and staying together in a near by apart Keep an EYE

An Old man and a Young man are working together in an office and staying together in a near by apartment. The Old Man takes 30 minutes and the Young 20 minutes to walk from apartment to office. If one day the old man started at 10:00AM and the young man at 10:05AM from the apartment to office, when will they mee?

Asked In TCS Priyabrat Padhy (11 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Rakesh Kumar  (11 years ago)

Ratio of old man speed to young man speed = 2:3

The distance covered by old man in 5 min = 10

The 10 unit is covered with relative speed=10/(3-2)=10 min

so, they will meet at 10:15 am.

Is this solution Helpfull? Yes (42) | No (20)  

dhirendra sisodiya  (11 years ago)

they will meet at 10:15 AM

Is this solution Helpfull? Yes (8) | No (18)  

RamanaKumar kondeti  (7 years ago)

from trail and error method from the options 10:15minutes the oldman:youngman takes 15:10(ratio) i.e 3:2 which satifies the condition 30 mintes for the oldman and 20 minutes for the youngman

Is this solution Helpfull? Yes (4) | No (3)  

Mrityunjay yadav  (5 years ago)

Let distance = x

speed of young man = x/20

Speed of old man = x/30

relative speed x/20−x/30=x/60

Distance traveled by old man in 5 min =5*x/30=x/6

Time taken by the young man to catch up the old man =Distance travelled /Relative speed=x/6*60/x =10 min

So,young man will catch up man the old man at 10:15 am.



Hence, 10:15am is the answer.

Is this solution Helpfull? Yes (4) | No   

Preethi  (5 years ago)

the difference of their speed is 10 mins the old man meet office by 10:30 am but the boy by 10:25 am so before 10:25 he should meet the old man but he started after 10:05 so minus that 10 mins from 10:25 we get 10:15 as the answer.

Is this solution Helpfull? Yes | No (1)  

Rahul Kumar Gupta  (5 years ago)

60
/
3 2 then relative speed is=3-2=1 and old man goes in 5min 5*3=15 then ans=10:15
/
20 30



/

Is this solution Helpfull? Yes | No (1)  

gowtham  (4 years ago)

ans: 0.4270833333333333

verified:

Is this solution Helpfull? Yes | No (3)  

johnnyjohnnynopapa  (3 years ago)

Ratio of speeds 30units/min : 20 units/min
relative speed 10 units/minutes
in 5 min old man travels 100units
100/(30-20)=10min
10min+5min =15min

Is this solution Helpfull? Yes | No   

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