Latest TCS Aptitude Question SOLUTION: What is the distance in cm between two parallel chords of length 32 cm & 24 cm in a circle of radius 20 cm. (a) 4 or 28 (b) 3 or

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What is the distance in cm between two parallel chords of length 32 cm & 24 cm in a circle of radius 20 cm.

(a) 4 or 28 (b) 3 or 21
(c) 2 or 14 (d) 1 or 7

Asked In TCS davish nigam (9 years ago)

Unsolved Read Solution (9)

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Avishek Bhowmick  (9 years ago)

a.
AB & Cd r 2 chords..& Ef is the distance b/w them... & o is the centre

NOw Using pythgorus
OF=((OC)^.5 +(CF)^.5)^.5=12
same we get OE=16
finally EF =(16-12) or (16+12)=4 or 28

Is this solution Helpfull? Yes (14) | No (1)  

SAHELI BISHNU  (9 years ago)

When chords are on opposite side .Draw two perpendiculars from the centre , these two perpendiculars would be bisecting the two chords. hypotenuse is 20, base 16 . Perpendicular distance is 12 . another hypotenuse is 20,base is 12 , prpendicular is 16 . Therefore distance is 12+16=28.Again 16-12= 4. (when chords are in same side)

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indrani banerjee  (9 years ago)

by using pythagoras its coming 16cm and 12 cm .
so answer will be either 28 or 4 , optn c answer.

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M.V.S.VARSHA  (9 years ago)

(c) 2 or 14

Is this solution Helpfull? Yes | No (4)  

Abhishek singh  (9 years ago)

Answer will be option D
i.e 1 or 7

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gagandeep  (9 years ago)

can some1 explain how?

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mounika.gaja  (9 years ago)

the ans is (a), draw the dig join end of the chords to center v vl get d ans

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Tarun Gupta  (9 years ago)

@gagandeep . perpendicular from center bisects the chord .. radius given and half of chord lenth . distance from center of one chord can be found this way . similarly for second chord

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Mr.Murtuza alam  (9 years ago)

ans:28,using pythagorous theorem

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