Latest TCS Aptitude Question SOLUTION: From the top of a 9 metres high building AB, the angle of elevation of the top of a tower CD is 30° and the angle of depression of the foot of the tower is 60°. Find the height o

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From the top of a 9 metres high building AB, the angle of elevation of the top of a tower CD is 30° and the angle of depression of the foot of the tower is 60°. Find the height of the tower?
a) 9m
b) 18m
c) 20m
d) 27m
e) None of these

Asked In TCS ANUP KUMAR GUPTA (9 years ago)

Unsolved Read Solution (3)

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Read Solution (3) :

Surit Datta  (9 years ago)

We have to find the value of CD. We use Sine rule to find the answer easily.
Sine rule is,
a/Sin A = b/Sin B = c/Sin C
according to the triangle BDE,
9/Sin 60 = x/Sin 30
so x = 9/sqrt(3)
in triangle BCD,
CD/Sin 30 =( 9/sqrt(3)) / Sin 60
which implies CD = 3
so height of tower is 9 + 3 =12

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aseef  (9 years ago)

We have to find the value of CD. We use Sine rule to find the answer easily. Sine rule is aSinA=bSinB=cSinC

In triangle BDE, 9Sin60=xSin30

So 93√2=x12⇒x=93√

In triangle BCD, CDSin30=93√Sin60

CD12=93√3√2⇒CD=3
So height of the tower = 9 + 3 = 12

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priyank bahl  (8 years ago)

answer is 18..
cos60=9/x

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