Latest TCS Aptitude Question SOLUTION: 87th no. of series 2,10,26,50....

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(#M40011843) TCS question Keep an EYE

87th no. of series 2,10,26,50....

Asked In TCS Sneha paliwal (11 years ago)

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indrajit hui  (11 years ago)

sum= 2+10+26+50 upto 87 terms
sum= 2+10+26 86th +87th trm
(by sub) 0=2+[8+16+24+ upto 86 terms]-87th trm
so 87th trm=2+8[1+2+......+86]
=2+8*86*87/2
=2+29928=29930

Is this solution Helpfull? Yes (20) | No (1)  

ABHINAV SINGH  (11 years ago)

answer is =29930
series is 2,10,26,50
like 1st term is 2 = 1^2+1
2nd term is 10= 3^2+1
3rd term is 26= 5^2+1
similarly 87 term is = 173^2+1=29930......
as we seen above that in 1st ,2nd,& 3rd term it is squire of corresponding odd numbers+1
since 1st odd no is 1(1*2-1),,,,,2nd odd no is 3 (2*2-1),,,,3rd odd no is 5(2*3-1).....similarly 87 odd no is (2*87-1)= 173......

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hassini  (11 years ago)

29930....
1 st term = 2
2nd term = 2+8(1)
3rd term = 2+8(1)+8(2)
.
.
87 th term =2+8(1)+8(2)+....8(86)

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dkn  (11 years ago)

Ans:29930
1 st term = 2
2nd term = 2+8*1
3rd term = 2+8*1+8*2
.
.
87 th term =2+8*1+8*2+....8*86
= 2+8*86*87/2
=29930

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SATISH VARADA  (11 years ago)

26570

1^2+1
3^2+1
5^2+1
7^2+1
.
.
.
.
163^2+1

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semanti dey  (11 years ago)

10-2=8
26-10=16
50-26=24
x-50=32
so tha ans is (50+32)=82

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