Latest TCS Aptitude Question SOLUTION: X ^ Y denotes X raised to power Y, find the last two digits (2361 ^ 4507) + (1741 ^ 3581)

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40011852) TCS question Keep an EYE

X ^ Y denotes X raised to power Y, find the last two digits (2361 ^ 4507) + (1741 ^ 3581)

Asked In TCS suprio Tarafder (11 years ago)

Unsolved Read Solution (11)

Is this Puzzle helpful?   (9)   (1) Submit Your Solution

Read Solution (11) :

Saurabh Pandey  (11 years ago)

these question are solved by simple techniques....actually

last two digits of 2361^4507 will
firstly taking power of 1^..=1
then multiplying second last digit of 2361 means 6 with last digit of power 4507 means with 7 that will be 7*6=42 .....taking last digit of 42 i.e. 2

joing 2 & 1 we get 21
similarly last 2 digit of 1741^3581=41

41+21=62

Answer. 62, for appropRiate proof visit tio sites related to puzzles...other than math4

Is this solution Helpfull? Yes (27) | No (2)  

Rishi Singh  (11 years ago)

62 it's too easy

Is this solution Helpfull? Yes (9) | No (7)  

vijayakumari  (11 years ago)

last 2 digit 61 and squering the 61,, 61^1=61,61^2=21(3721),61^3=81(226981)
61^4=41,61^501 therefore 5terms we getting,power 4507/5=remain(2)
41^1=41,41^2=81,41^3=21,41^4=61,41^5=01
3581/5=remain(1)..... remain 2place value=21
remain 1place value=41 total =62

Is this solution Helpfull? Yes (7) | No (3)  

sneha verma  (11 years ago)

for here we know thatif last digit of a no. is odd except 5 then if that no is raised to a power which is multiple of 20 then last two digits will be (01).......
now (2361)^4507=(2361)^4500*(2361)^7=> for last two digits it will be
(61)^4*(61)^3=> (1384584141)*(226981).... if only last two digits are taken for both then it will be 41*81=3321
having last two be 21
and for 1741^3580*1741^1=1741
so last two digits be 41
now adding both we have.... 21+41=62
thus 62 will be the last two digits

Is this solution Helpfull? Yes (7) | No (2)  

Saurabh Pandey  (11 years ago)

its not easy for every1 brother .....persons who have solved these type of puzzles earlier ...they only can solve this ques....

so please dont say n e thing easy.... @rishi singh

Is this solution Helpfull? Yes (3) | No   

neha   (11 years ago)

@rishi : can u plz explain ur answer

Is this solution Helpfull? Yes (2) | No (3)  

nishi agarwal  (11 years ago)

@rishi : plz xplain...how it came 62

Is this solution Helpfull? Yes (1) | No (1)  

keerthi  (11 years ago)

4507/5 remainder=2
3581/5 remainder=1

Is this solution Helpfull? Yes (1) | No   

Souvik Basak  (9 years ago)

for 2361^4507
first take last term of 2361 which is 1
and find 1^7=1
now take 2nd last digit of 2361 which is 6 and here 6*7=42;
here 7 is the last digit of 4507..
now combine 42 and 1 which gives 421..its last 2 digits are 21-------A)
follow this also for 1741^3581 it will give 41-------B)
Add A+B i.e 41+21=62..
hence correct answer is 62..
Hope you will understand..

Is this solution Helpfull? Yes (1) | No (1)  

semanti dey  (11 years ago)

how 10's digit of 61^4507 is comming 21..pls xplain...its not clr..any power of 6 produce 6 to?

Is this solution Helpfull? Yes | No (1)  

snehil  (11 years ago)

6*7=42
so last digit 21
and 4*1=4
so last digit 41
ie ans will be=41+21=62

Is this solution Helpfull? Yes | No (2)  

Please Login to Read Solution.