Latest TCS Aptitude Question SOLUTION: 5. Find the probability that a 3 digit number formed by using the digits 1, 3, 6, 9 without repetition, is divisible by 4. a. 1/2 b. 1/3 c. 1/4 d. 1/5

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5. Find the probability that a 3 digit number formed by using the digits 1, 3, 6, 9 without repetition, is divisible by 4.
a. 1/2
b. 1/3
c. 1/4
d. 1/5

Asked In TCS rajendra prasad (9 years ago)

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thiyagarajan s  (9 years ago)

if the number should be divisible by 4 then last two digits must be multiples of 4
so the ways of locating unit digit is 3 ways out of (3,6,9)
tenth digit is 2 ways
hundredth digit is 1 way since repetition is not allowed
total ways = 1*2*3 =6
Total sample space= 4!
probability = 6 / 24 = 1 / 4

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monika sharma  (9 years ago)

ans is (c)1/4.

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JAKEER  (9 years ago)

ans=1/2
( divisible by 4 implies the last two ns should be divisible by 4 i,e only 16 so only 1 way
2c1*1/4c3=2/4=1/2)

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Mamta  (9 years ago)

ANS =1/2
divisible by 4 implies the last two nums should be divisible by 4 . that are 16 and 36 so two ways.
hundredth palce disgit can be chosen in total 4 ways,
so p=2/4=1/2

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RAMYA  (9 years ago)

divisible by 4 implies the last two nums should be divisible by 4 . that are 16 and 36 so two ways.
there is no repetition means remaining 2 numbers ,2way
total 2+2=4
ans:4

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