Latest TCS Aptitude Question SOLUTION: A CIRCLE HAS 29 POINTS ARRANGED IN A CIRCULAR FASHION CLOCKWISE FROM 0 TO 28.A bug moves clockwise on the circle by foolowing rule: if it is point i on the circle it moves clockwis

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40011998) TCS question CIRCLE Keep an EYE

A CIRCLE HAS 29 POINTS ARRANGED IN A CIRCULAR FASHION CLOCKWISE FROM 0 TO 28.A bug moves clockwise on the circle by foolowing rule:
if it is point i on the circle it moves clockwise by i+r places, where r is the remainder when i is divided by 17. Thus if it is at point 5, then it moves in one second clockwise to further 1+5; i.e at 11 position. If it is at position 28 it moves to 1+11 i.e 11 position in one second.
If he starts at point 0; where will he be after 2012 seconds?

Asked In TCS dk (11 years ago)

Unsolved Read Solution (11)

Is this Puzzle helpful?   (27)   (7) Submit Your Solution

Read Solution (11) :

jayasri  (11 years ago)

0sec-1+0%17=1 1st poss
1sec 1+1%17=2 2+1=3rd poss
2sec 1+3=4 4+3=7th poss
3sec 1+7=8 7+8=15th po
4 sec 1+14%17=15 15+15=30=2nd poss
5sec 1+2%17=3 3+2=5th poss
6sec 1+5%17=6 6+5=11th poss
7th 1+11%17=12 12+11=23th poss
8th 1+23%17=1+6=7 7+23=30=1st poss
after 7th poss circle repeates...
2012%8=4
15th possition

Is this solution Helpfull? Yes (31) | No (7)  

gopal kumar  (11 years ago)

ans is 15
at 1sec o%17+1=1
at 2 sec 1+1%17+1=3
at3 sec 3+3%17+1=7
at 4sec 7+7%17+1=15
at 5 sec 15+15%17+1=3
it will repet after 3second
hence 2012-2=2010
2010/3
=0
hence it will be 15

Is this solution Helpfull? Yes (8) | No (3)  

Joychand  (11 years ago)

thnks to JAYASRI but the positions repeat for every 8 secs (or 8 pos)
Starting from 0 pos,
pos. after 1sec=0+(1+0%17)=0+(1+0)=1
,, ,, 2sec=1+(1+1%17)=1+(1+1)=3
,, ,, 3sec=3+(1+3%17)=3+(1+3)=7
,, ,, 4sec=7+(1+7%17)=7+(1+7)=15
,, ,, 5sec=15+(1+15%17)=15+(1+15)=31=2
,, ,, 6sec=2+(1+2%17)=2+(1+2)=5
,, ,, 7sec=5+(1+5%17)=5+(1+5)=11
,, ,, 8sec=11+(1+11%17)=11+(1+11)=23
,, ,, 9sec=23+(1+23%17)=23+(1+6)=30=1
so poss repeat for every 8 secs
2012%8=4
ANS 15 POSITION

Is this solution Helpfull? Yes (6) | No   

Satheesh  (11 years ago)

Ans is:7

position calculation value
-------- ----------- -----
0 1+0/17 1
1 1+1/17 2
3 1+3/17 3
7 1+7/17 8
15 1+15/17 16
2 1+2/17 3
5 1+5/17 6
11 1+11/17 12
23 1+23/17 7
1 Cycle formed

1-3-7-15-2-5-11-23-1 Every 8 second the bug return to position '1'
2012-1 (number of digit doesn't involved in the cycle)=2011
2011/8 = 3 (remainder)
so the third position in the cycle is '7'.
hope you've got it.

Is this solution Helpfull? Yes (5) | No (7)  

Swati  (11 years ago)

the ans is 3..bcoz when he starts from position 0..
here i=0 and i divided by 17 will also give zero.therefore i+r(0+0) is again zero and hence its first move is only zero and will not be able to move further as this continues for infinite seconds.
therefore,ans is ZERO.

Is this solution Helpfull? Yes (4) | No (4)  

Pawan Ahuja  (11 years ago)

ans is o..

Is this solution Helpfull? Yes (1) | No (5)  

Swati  (11 years ago)

ans is ZERO

Is this solution Helpfull? Yes (1) | No (5)  

Satheesh  (11 years ago)

thanks jayasri. I made a mistake. answer would be 15. sorry guys.

Is this solution Helpfull? Yes (1) | No   

shivesh  (11 years ago)

jayshri a small mistake at the end of 4th sec u have written 14 in place of 15

Is this solution Helpfull? Yes (1) | No   

Kumar Purnendu  (11 years ago)

0sec-1+0%17=1 1st poss
1sec 1+1%17=2 2+1=3rd poss
2sec 1+3=4 4+3=7th poss
3sec 1+7=8 7+8=15th po
4 sec 1+14%17=15 15+15=30=2nd poss
5sec 1+2%17=3 3+2=5th poss
6sec 1+5%17=6 6+5=11th poss
7th 1+11%17=12 12+11=23th poss
8th 1+23%17=1+6=7 7+23=30=1st poss
after 7th poss circle repeates...
2012%8=4
15th possition

Is this solution Helpfull? Yes (1) | No   

vignesh  (10 years ago)

the ans is 0..

bcoz when he starts from position 0..

here i=0 and i divided by 17 will also give zero.therefore i+r(0+0) is again zero and hence its first move is only zero and will not be able to move further as this continues for infinite seconds.

therefore,ans is ZERO.

Is this solution Helpfull? Yes | No (1)  

Please Login to Read Solution.