Latest TCS Aptitude Question SOLUTION: 1,2,3,4,5,6,7,8,9,1,0,1,1,1,2,1,3,1,4,1,5....find 25322 term?

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(#M40012172) TCS question Keep an EYE

1,2,3,4,5,6,7,8,9,1,0,1,1,1,2,1,3,1,4,1,5....find 25322 term?

Asked In TCS Arit (11 years ago)

Unsolved Read Solution (19)

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Akash Gupta  (11 years ago)

ans is 6.
explanation- 1 to 100 - 192 term
101 to 1000- 2701 term
1001 to 6500-22000 term
so 25322-(192+2701+22000)=429th term have to find
6501 to 6600 = 400 term
6601 to 6607 = 28 term
s0 next term is 6608.
so ans is 6.

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goldy  (11 years ago)

see
the series is 1,2,3,4,5,6,7,8,9=9 terms
and further 1,0,1,1,1,2,1,3,1,4,1,5,1,6,1,7,1,8,1,9........9,9=180 terms
(just take the series as 10,11,12,13,14,15,,,,,99 then the no. of term in this series is=90 therefore the original no. of term in the series 1,0,1,1,2,1,3,1,4,,,,,,,,,,9,9=180)
similarily for 1,0,0,1,0,1,,,,,,,,,,,,,,9,9,9 no. of terms=900*3=2700
note that so far we have find total 2899 terms and we have o find (25322-2899=22423th term from here on)
further the series is 1,0,0,0,1,0,0,1,,,,,,,,,9,9,9,9= total 9000*4=36000terms
now in the above series we have to find the 22423th term
thus 36000-22423=13577
13577/4=3394.25
thus the 3394th term is 10000+(3394-1)*1=13393
next is 13394 thus the 25322th term is=1

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Shubham  (11 years ago)

1,2,3.....9=9 terms
1,0,1,2,.....9,9=90*2=180 terms
1,0,0,1,0,1......9,9,9=900*3=2700 terms
2700+180+9=2899
remaining terms:25322-2889=22433

so no. of 4 digit numbers:22432/4=5608
thus the 25321 term will be 999+5608=6607

next number is(6,6,0,8)
Ans=25322 term will be 6

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Gaurav Bhadama  (11 years ago)

no. of terms from 1 to 9= 9*1=9
no. of terms from 10 to 99 = 90*2 = 180
no. of terms from 100 to 999 = 900*3= 2700
no. of terms from 1000 to 9999 = 9000*4 = 36000

now, add first three...i.e 9+180+2700= 2889
there are 2889 terms from 1 to 999

how more we need--->> 25322-2889= 22,433

as there are 4 digits in each term from 1000 above, divide 22,433 by 4

(or else divide 22,432 by 4...coz it completely divides it)

22,432/4 = 5,608 (including 1000)

so, 999+5608=6607
first '6' in 6607 is 25321st term....so the next '6' is 25322nd term...:)

m i wrong??

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ASHISH KUMAR  (11 years ago)

1 dgt -> 9
2 dgt -> (10-99)=90*2(each contain 2 term)
likewise
3 dgt -> 900*3
4 dgt -> 9000*4=36000 (>25322) so skip here..
add all above three..
sum=2889
(25322-2889)=22433
22433/4= 5608.25=5609th 4 dgt no.
thus ans will be =1000+5608=6608(since 1000 is included that' why it is 5609th term)
thus term will be 8...

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shyam salona  (11 years ago)

total numbers upto 3 digit are 9+90*2+900*3=2889
25322-2889=22533
as all no will be of 4 digits now so rank of no will be
22533/4=5633.25
means that desired no will be the first term of 5634th no in 4 degit series so
5634 no=1000+(5634-1)1=6633
hence required ans is 6

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goldy  (11 years ago)

SORRY GUYS FOR EARLY MISHAP:
HERE IS THE SOLUTION-
1,2,3,4,5,….9 total terms=9
1,0,1,2,1,3,1,4,,,,,,,,,9,9 total terms=90*2=180
1,0,0,1,1,1,1,1,2,,,,,,9,9,9 total terms=900*3=2700
Thus sofar we have came to 2889th term i:e,9
Now 1,0,0,0,1,0,0,1,1,0,0,2,,,,,,,,,,,,,,,,,,,9,9,9,9
Total terms=9000*4=36000
But we have to stop the discussion at 25322-2889=22433th term
Thus we will find 22433th term in the above series
22433/4=5608.75
Now the 5608th term in the series1000,1001,,,,,,,,,,,,,,,9999
Is=1000+(5608-1)*1=6607
Rank of 6607 in the series1,0,0,0,1,0,0,1,,,,,,,,,9,9,9,9 is=5608*4=22432
Thus 22432+2700+180+9=25321th term
Now the 25322th term will be in 6,6,0,8
Thus 25322th term is 6……

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Harshita  (11 years ago)

goldy has done little mistake he shud hve subtracted from 10000 not added as u r counting from back...6605 is what u get,ans shud be 0

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chiru  (11 years ago)

can any xplain it...

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gaurav garg  (11 years ago)

ans 9
because 4091th=999 ie9
then 21228 digit are left and

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Anubhav Kumar  (11 years ago)

@GOLDY pls xplain the last 3 lines.

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dhivya  (11 years ago)

@goldy how 2899 came 9+180+2700=2889 only rite,then last step is not clear please explain

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Lovejeet Singh  (11 years ago)

any other method to solve ??

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kanika  (11 years ago)

@goldy please explain last three line of urs??

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priyanshu saxena  (11 years ago)

plz yyr xplain properly nt able 2 get the solution correctly

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Arka Laha  (11 years ago)

1,2,3,...... in this series we cn see that 10th term 1 30th term is 2 50th term is 3 so 10+(n-1)*20=25310

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Arka Laha  (11 years ago)

25310

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Arka Laha  (11 years ago)

i dont know why but the full solution is not coming........ last time i am trying 25310

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Arka Laha  (11 years ago)

n=1266 again 1+(1266-1)*1=1266 so 2310th term is 1 next is 2 then 6 so 2322nd term is 1.

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