Latest TCS Aptitude Question SOLUTION: In how many ways a team of 11 must be selected from 5 men and 11 women such that the team must comprise of not more than 3 men? a. 1565 b. 1243 c. 2256 d. 2456

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In how many ways a team of 11 must be selected from 5 men and 11 women such that the team must comprise of not more than 3 men?
a. 1565
b. 1243
c. 2256
d. 2456

Asked In TCS Aravind Kumarasamy (9 years ago)

Unsolved Read Solution (9)

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TANUSHREE GHOSH  (9 years ago)

c.2256
(5c3*11c8+5c2*11c9+5c1*11c10+11c11)

Is this solution Helpfull? Yes (15) | No   

RAMYA  (9 years ago)

3 mangoes and 4 apples costs Rs 85. 5 apples and 6 peaches costs Rs. 122. 6 mangoes and 2 peaches cost Rs.114. what is the combined price of 1 apple, 1peach and 1 mango?
(a)37
(b)39
(c)35
(d)36
28
27
26 canu any tell me the ans of this question

Is this solution Helpfull? Yes (12) | No   

pranav patel  (9 years ago)

As we can take "atmost" 3 Men. So Combinations of (Men,Women) will be {(0,11),(1,10),(2,9),(3,8)}
Therefore --> 11C11 + 5C1 x 11C10 + 5C2 x 11C9 + 5C3 x 11C8
--> 2256

Is this solution Helpfull? Yes (6) | No   

Digvijay Pratap Singh  (9 years ago)

(5C0*11C11 ) + (5C1*11C10) + (5C2*11C9) + (5C3*11C8) = 2256

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Ram  (9 years ago)

1 apple +1 mango + 1 peaches = 37

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Ajith Gowda  (9 years ago)

1 Apple =10
1Mango=15
1Peaches=12
1Apple+1Mango+1Peaches=37

Is this solution Helpfull? Yes (2) | No   

Ramana Jajula  (9 years ago)

Dear @Ramya,
Note: It is 114 not 144.
3m + 4a = 85 ..(1)
5a + 6p = 122 ..(2)
6m + 2p = 114 ..(3)
(1) x 2 => 6m + 8a = 170
(3) => 6m + 2p = 114
Solving we get 8a - 2p = 56 ..(4)
(2) => 5a + 6p = 122
3 x (4) = 24a - 6p = 168
Solving we get a = 10, p = 12, m = 15
So a + p + m = 37

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Rohit Ranjan  (9 years ago)

ways of selection : 5c4 x 11c7 + 5c5 x 11c6

Is this solution Helpfull? Yes | No (3)  

RAHUL GAUTAM  (9 years ago)

5c3*11c8+5c2*11c9+5c1*11c10+5c0*11c11 = 2256

Hence, c. 2256

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