Latest m4maths Aptitude Question SOLUTION: Sum of three positive even integers is 30 and their product is 960. Sum of the two smaller integers will be?

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(#M40013114) M4MATHS question Keep an EYE

Sum of three positive even integers is 30 and their product is 960. Sum of the two smaller integers will be?

Asked In m4maths sathyapriya (11 years ago)

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mogal samrat  (11 years ago)

let three even numbers is x,x+2,x+4then
3x+6=30=>x=8 then series is 8,10,12 then product:8*10*12=960.
small digit sum is:8+10=18

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Shashi  (11 years ago)

18

Sum of three positive even integers is 30 ... 8+10+12
and their product is 960-- 8*10*12
. Sum of the two smaller integers will be 8+10=18

Is this solution Helpfull? Yes (3) | No (1)  

Manami Bhunia  (11 years ago)

let the 1st digit be x
now x+(x=2)+(x+4)=30
we get x=8
then 8 +10=18

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shivendra pratap singh  (11 years ago)

three even no be (x+2),(x+4),(x+6)
then there sum is
(x+2)+(x+4)+(x+6)=30
so x is 6
sum of smaller no is (x+2)+(x+4)=6+2+6+4=18

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sunny saurav  (11 years ago)

it hasn't been mentioned that the 3 integers are consecutive!
>>so, since the '0' in '960' can only be present if AxBxC contains '10' as an integer. rest two integers' product has to be 96. 12x8 is the only possibility within the given constraints.
thus, 8, 10, 12 are the integers and 18 is the total.

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jatin patware  (11 years ago)

ans=18
hence numbers are 8,10,12
8+10+12=30
8*12*10=960

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