Latest Google Aptitude Question SOLUTION: Find the greatest 4 digit number that satisfies the following condition's 1)The number divided by 10 gives reminder 9 2)The number divided by 9 gives reminder 8 3)The number divide

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(#M40013693) GOOGLE Numerical Ability question Reminder Question Keep an EYE

Find the greatest 4 digit number that satisfies the following condition's
1)The number divided by 10 gives reminder 9
2)The number divided by 9 gives reminder 8
3)The number divided by 8 gives reminder 7
4)and so on....
Clue:-) Ans is greater 5000

Asked In Google (11 years ago)

Solved M.R.kartheek Read Solution (4)

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Read Solution (4) :

M.R.kartheek  (11 years ago)

Answer is very simple:
take L.C.M of numbers(2,3,4,5,6,7,8,9,10) = 2520
for that we are not checking 1 so 2520 - 1 = 2519
so the next possibility after 2519 is 2519 + 2520 = 5039
after 5039 the next possibility is 5039 + 2520 = 7559
so the four digit numbers that satisfy the conditions are
1)2519
2)5039
3)7559
so the greatest four digit number is 7559....
enjoyyyy....

Is this solution Helpfull? Yes (27) | No (5)  

Amit kumar  (11 years ago)

Take L.C.M of numbers(2,3,4,5,6,7,8,9,10) = 2520
the greatest 4-digit no. is 9999
we divide 9999 by 2520 and the remainder is 2439.

Step 1==> we subtract the remainder from 9999.
9999-2439 = 7560
Step 2==> Subtract 1 from 7560
7560-1= 7559 (this is required Ans.)
Note:- 1= C.D of divisor and respective remainder given in ques
9-8 = 8-7= 7-6= 6-5= 5-4= 4-3= 3-2= 2-1= 1

Is this solution Helpfull? Yes (16) | No (2)  

praveendas  (8 years ago)

lcm of 10,9,8 is 360
the greatest possible four digit number is9999
divide the number by 360 we get remainder of 2799
subtract remainder from 9999 we get=9999-2799=7200
then sub 1 from ans=7199...............
that's it the number which satisfy the above conditions

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Ajay Thakur  (7 years ago)

first we need to find LCM of 10,9,8 because remainder differrence is equal.
LCM of(10,9,8)=360
than divide largest four digit number by 360
i.e 9999/360
we got remainder 279
subtract that remainder with 9999
we got 9720 which is the largest number required.

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