Latest MBA Aptitude Question SOLUTION: 4 dices are thrown simultaneously. find the probability that 2 of them show same face and remaining 2 show different faces??

1) 4/9
2) 5/9
3) 11/18
4) 7/9

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(#M40013944) MBA question permutations and combinations, probability Keep an EYE

4 dices are thrown simultaneously. find the probability that 2 of them show same face and remaining 2 show different faces??

1) 4/9
2) 5/9
3) 11/18
4) 7/9

Asked In MBA (11 years ago)

Unsolved Read Solution (4)

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ankit rawat  (11 years ago)

ans is (6X6X20)/(6^4)= 5/9

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Gaurav Dudeja  (11 years ago)

Total Outcome=6x6x6x6

Favorable 16x6

so 16x6/6x6x6x6=2/27

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abcd  (9 years ago)

Select a number which occurs on two dice out of six numbers (1, 2, 3, 4, 5, 6). This can be done in , ways.
Now select two distinct number out of remaining 5 numbers which can be done in ways. Thus these 4 numbers can be arranged in 4!/2! ways.
So, the number of ways in which two dice show the same face and the remaining two show different faces is

=> n(E) = 720

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Kanika  (9 years ago)

total possible outcomes =6*6*6*6
now,
ways in which two positions are selected from 4 is 4C2.
Now the rest two places are filled as 6!/2!.
so we get 4C2*6*5*4/6*6*6*6=5/9

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