Latest Elitmus Aptitude Question SOLUTION: how many ways are there to choose four cards of different suits and different values from a deck of 52 cards.

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Probability

Elitmus Question Papers:

(#M40151348) ELITMUS Numerical Ability question Keep an EYE

how many ways are there to choose four cards of different suits and different values from a deck of 52 cards.

Asked In Elitmus (9 years ago)

Unsolved Read Solution (11)

Is this Puzzle helpful?   (15)   (6) Submit Your Solution Probability

Read Solution (11) :

siddharth prakash singh  (9 years ago)

There are 4 suits having 13 cards each.
So to choose different value card from each suit, we have 13 option for first suit (say diamond), then we will have 12 option for next suit (say heart), then we will have 11 option for next suit (say club) and lastly we have only 10 option for last suit (say spade)
so total no of ways = 13c1 x 12c1 x 11c1 x 10c1 = 17160 ways.

Is this solution Helpfull? Yes (36) | No (3)  

shravan kumar jha  (9 years ago)

13c1 x 12c1 x 11c1 x 10c1=17860 ways

Is this solution Helpfull? Yes (3) | No (2)  

Pankaj Kumar Shee  (9 years ago)

13c1*12c1*11c1*10c1=17160

Is this solution Helpfull? Yes (3) | No   

Apoorva R  (8 years ago)

Each suit has 13 cards.So to choose 4 cards of different suits we have 13C1 ways each.Total number of ways is 13C1*13C1*13C1*13C1 ways.

Is this solution Helpfull? Yes (3) | No (3)  

bns  (9 years ago)

from 52 cards select one=52c1
after eliminating one suit and one value i.e 13+3=16, we get 36.
again eliminate one value and suit card from this 36 cards i.e 12 each in 3 suit, we get 22.
similarly again eliminating we get 10.
so total is=52c1*36c1*22c1*10c1=411840

Is this solution Helpfull? Yes (1) | No (5)  

shailendra singh  (8 years ago)

@siddharth prakash...... i think the answer that you took out should be divisible by 4! ..... as one by one selection leads to arrangement.....pls reply

Is this solution Helpfull? Yes (1) | No   

shankar sahu  (9 years ago)

13C1*12c1*11c1*10c1

Is this solution Helpfull? Yes | No   

AKHIL KALRA  (8 years ago)

ans shold be as......> (4c1*13c1)*(3c1*12c1)*(2c1*11c1)*(1c1*10c1)=411840

Is this solution Helpfull? Yes | No   

vikash rawat  (8 years ago)

10*11*12*13=17160

Is this solution Helpfull? Yes | No   

sangam jain  (8 years ago)

Selecting 1st card=13C1
Selecting 2nd card=12C1
Selecting 3rd card=11C1
Selecting 4th card=10C1
so multiply and get the answer

Is this solution Helpfull? Yes | No   

Neha Mitali  (8 years ago)

different suits means we have 13 cards of each suite
now,we have 13 option 2 choose 1st card
12 for 2nd card
11 for 3rd card
10 for 4th card
thus,13*12*11*10

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.