Latest Elitmus Aptitude Question SOLUTION: How many 3 digit numbers can be formed using digits 1,2,3,4 and 5 without repeatation, such that number is divisible by 6. (a) 4 (b) 6 (c) 8 (d) 10

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(#M40151464) ELITMUS Numerical Ability question Asked on 26th April Keep an EYE

How many 3 digit numbers can be formed using digits 1,2,3,4 and 5 without repeatation, such that number is divisible by 6.
(a) 4 (b) 6 (c) 8 (d) 10

Asked In Elitmus siddharth prakash singh (9 years ago)

Unsolved Read Solution (11)

Is this Puzzle helpful?   (11)   (4) Submit Your Solution Permutation and Combination

Read Solution (11) :

MR. X  (9 years ago)

8 is ans
312,132,432,342,324,234,534,354

Is this solution Helpfull? Yes (18) | No (1)  

mukund  (9 years ago)

8. Is the correct answer

Is this solution Helpfull? Yes (3) | No (1)  

satyadev  (9 years ago)

if the no is to b divsible by 6 then it should also divisible by 2 and 3

for 2 the rule is last no should b even so here v have 2 nd 4
so thn no vll lyk this __2 nd __4

and the no should not to b repeated so now v cannt use 2 nd 4 , so now v have 1,3,4,5 for no ending vth 2 nd 1,2,3,5 for no ending vth 4
for divisble vth 3 the rule is total of that no should b mutiple of 3 for no ending vth 2 means v can have 312,132,432,342
nd for no ending vth 4 means 324,234,534,354

Is this solution Helpfull? Yes (3) | No (3)  

SHANUR RAHMAN  (8 years ago)

as the no have to b divisible by 6 then it should be divisible by 2 and 3 both....that means no. have to be even as well as the sum of the no. should be divisble by 3..

so...we have 2 and 4 for the unit place.....

now for _ _ 2 we have 4 combinations as 2 has been used we cant use this....so possible combo will be 1,3 or3,1or4,3or3,4....i.e.....=4 nos...

now for _ _ 4 we have 2,3 or 3,2 or 3,5 or 5,3...i.e= 4nos....

so total nos will be=8

Is this solution Helpfull? Yes (2) | No (1)  

aman aditya  (9 years ago)

ans>8
312,132,432,342,324,234,534,354

Is this solution Helpfull? Yes (1) | No (1)  

ABHISHEK KUMAR SINGH  (9 years ago)

possible numbers are 132,312,642,462,162,612,432,342, 234,324,624,264,564,654,534,354. BUT 16 is not given in option.

Is this solution Helpfull? Yes (1) | No (14)  

JUGAL KHAJURIYA  (9 years ago)

How 8 is possible

Is this solution Helpfull? Yes | No   

ROHINI KUMAR D  (9 years ago)

please explain the answer

Is this solution Helpfull? Yes | No (1)  

mahesh kumar p  (9 years ago)

8 is ans
312,132,432,342,324,234,534,354

Is this solution Helpfull? Yes | No (1)  

shruti jain  (9 years ago)

5C3 => 5C2 [ ncr = ncn-r]
so 5*42*1 = 20/2
i.e 10 ans will be 10

Is this solution Helpfull? Yes | No (5)  

shubham  (8 years ago)

ans - 10
324, 534 312 612 342
234 354 132 162 432

Is this solution Helpfull? Yes | No (4)  

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