Latest Elitmus Aptitude Question SOLUTION: a goes to place x and b goes to place y. after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that

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(#M40151587) ELITMUS Numerical Ability question permutation Keep an EYE

a goes to place x and b goes to place y.
after a travelled 180 km more than b they together meet at a point between xy. they together had their lunch for half an hour. after that a took 2 hrs to reach x and b took 4.5 hrs to reach y. find distance between x and y?
a)900km b)540km c)720km d) not remember

Asked In Elitmus MR. X (9 years ago)

Unsolved Read Solution (6)

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Read Solution (6) :

jitendra singh  (8 years ago)

let speed of A be-------Sa
let speed of B be--------Sb
let the distance covered by B while going to position XY be-----------x
so distance covered by A in same time while going to XY is----------180 +x(it's given in the question)
so total distance b/w X and Y is=x+(x+180)
while going to position XY :-
time taken by A = time taken by B
(x+180)/Sa= x/Sb
Sa/Sb=(x+180)/x---------------------1

after lunch:-
A.C.T(according to question)
Sa=x/2
Sb=(x+180)/4.5

dividing Sa/Sb=(x*4.5) / ((x+180)*2)--------------------2

equating equations 1 and 2
9/4 = (x+180)^2 / x^2
now taking square root on both sides we get

3/2 = (x+180) / x

x=360
therefore distance between x and y =x+(x+180)=900km
option A is correct

Is this solution Helpfull? Yes (18) | No (1)  

Pushpak  (9 years ago)

answer is 900
at the meeting point time is constant
s1/s2= D1/D2
solving by option taking 900
s1/s2=540/360=3/2 .............. (1)
it means a have to travel 360 km in 2 hrs speed of a= 180 kmph
by eq(1) speed of b is 120kmph and it will take 4.5 hrs to travel 560 km.
thus 900 kn is answer

Is this solution Helpfull? Yes (10) | No (10)  

bns  (9 years ago)

condition for velocity is missing

Is this solution Helpfull? Yes (3) | No (4)  

AKHIL KALRA  (8 years ago)

ans is 540 km
let speed of A be-------Sa
let speed of B be--------Sb
let the distance covered by B while going to position XY be-----------x
so distance covered by A in same time while going to XY is----------180 +x(it's given in the question)
so total distance b/w X and Y is=x+(x+180)
while going to position XY :-
time taken by A = time taken by B
(x+180)/Sa= x/Sb
Sa/Sb=(x+180)/x---------------------1

after lunch:-
A.C.T(according to question)
Sa=x/2
Sb=(x+180)/4.5

dividing Sa/Sb=(x*4.5) / ((x+180)*2)--------------------2

equating equations 1 and 2
9/4 = (x+180)^2 / x^2
now taking square root on both sides we get

3/2 = (x+180) / x

so ,x =180
and total distance is = x+(x+180)=540 km

Is this solution Helpfull? Yes (2) | No (6)  

sourabh jain  (9 years ago)

180 km wil tak 2.5 hr
ans 468

Is this solution Helpfull? Yes | No (6)  

shubham  (9 years ago)

180 km in 2.5hr ,speed of b will become=72km/h
sa=1.5*72 =108 km/h
total dist=540km

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