Latest GRE Aptitude Question SOLUTION: The minimal distance between any point on the sphere (x-2)^2 + (y-1)^2 + (z-3)^2 = 1 and any point on the sphere (x+3)^2 + (y-2)^2 + (z-4)^2 = 4 is (A) 0 (B) 4 (C) Sqrt(27) (D) 2

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(#M40151761) GRE Numerical Ability question Point distance on the sphere Keep an EYE

The minimal distance between any point on the sphere (x-2)^2 + (y-1)^2 + (z-3)^2 = 1 and any point on the sphere (x+3)^2 + (y-2)^2 + (z-4)^2 = 4 is
(A) 0
(B) 4
(C) Sqrt(27)
(D) 2(Sqrt2 + 1)
(E)3(Sqrt3 – 1)

Asked In GRE Aashu (9 years ago)

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