Latest Elitmus Aptitude Question SOLUTION: 1/a - 1/b = 1/c where a,b,c are single digit number and b > a . Then we have to find how many values are possible for a,b,c as per the given conditions..?

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(#M40151934) ELITMUS Numerical Ability question Quant Section Keep an EYE

1/a - 1/b = 1/c where a,b,c are single digit number and b > a . Then we have to find how many values are possible for a,b,c as per the given conditions..?

Asked In Elitmus deepak kumar singh (9 years ago)

Unsolved Read Solution (14)

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SAURABH KUMAR   (8 years ago)

ans is 6 : (1,2), (2,3), (2,4), (2,6), (3,6), (4,8)
you have to solve it manually.. there is no specific formula for this..

Is this solution Helpfull? Yes (9) | No (1)  

manikandan  (9 years ago)

b-a/ab=1/c---(1) b can take values as 2,3,4,5,6,7,8,9:a can have 1=>8 possibilities
b can take values as 2,3,4: a can have 2=>3 possibilities
b can take 2,3 :a can have 3=>2 possibilities.(the tricky part here is b*a=3*3=9 is the max value allowed(single digit) so a can take up ly 1,2,3 total 13 possible

Is this solution Helpfull? Yes (4) | No (1)  

Gourab Dutta  (9 years ago)

c=36
b=8
a=8

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Gourab Dutta  (9 years ago)

c=36
b=8
a=8

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Gourab Dutta  (9 years ago)

c=36
b=8
a=8

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Gourab Dutta  (9 years ago)

c=36
b=8
a=8

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Gourab Dutta  (9 years ago)

c=36
b=8
a=8

Is this solution Helpfull? Yes | No (2)  

CHANDRA SHEKHAR BHARDWAJ  (9 years ago)

Answer=10 because,when b=2,a=1,when b=3,a=1,2 when b=4,a=1,2 when b=5 a=1,similarl y for b=6,7,8,9 a=1 so total 10 different combination of a,b,c.

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Yash Puri  (9 years ago)

tha ans wer is 3 sets possible as a=2,b=3,c=6;; a=1,b=2,c=2;;; a=2,b=4,c=4

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satyam  (9 years ago)

ans will be 8!

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DANISH BILAL  (9 years ago)

3 sets of solution..
1/a-1/b=1c
=>(b-a)/ab=1/c..where a,b and c should be single digit..
b=2,a=1
b=3,a=2
b=4,a=2..
for others c will be greater than 9..

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Aakash Chandnani  (8 years ago)

Kindly note , a b c are SINGLE DIGIT NUMBER and as they are different alphabets so they should have different values...
Solving it manually i got 2 possible solutions...
a=2 b=3 c=6
AND
a=2 b=6 c=3

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santosh  (8 years ago)

SOUMEN MAITY study first

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Anirban maity  (8 years ago)

Ans will be 36.
B>A.
So B=9,then A=8,7,6,5,4,3,2,1-i.e. 8diffrnt values for c.
Thus forB=8,7values for C.
B=7,6values..so on upto B=2.
When b=1thn a=0, c will be same as b. Tht case will nt be considered.
So total possibl solutn.=8+7+6+5+4+3+2+1=36 sets.

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