Latest Elitmus Aptitude Question SOLUTION: ABCD is a rectangle. side AB is produced to E such that BC=BE. A circle is drawn with AE as diameter. The line BC is produced to meet the circumference of circle at point F. What i

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(#M40152531) ELITMUS Numerical Ability question APTITUDE Keep an EYE

ABCD is a rectangle. side AB is produced to E such that BC=BE. A circle is drawn with AE as diameter. The line BC is produced to meet the circumference of circle at point F.
What is the length of BF.
options I don't remember but it was given in term of l and b.

Asked In Elitmus raksha singh (8 years ago)

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SANTU MAITY  (8 years ago)

As given in the question that BC produced meets the circumference of the circle that means BC must be the smaller side of the rectangle.

Let the sides of the rectange ; AB = a and BC = b

Radius of the circle will be : AE/2 = (AB + BE) /2 = (AB + BC) /2 = (a+b) /2

Therefore OE = OF = (a + b) / 2

OB = (OE - BE) = ( a + b ) / 2 - b = ( a - b ) /2

Therefore; BF^2 = OF^2 - OB^2 = [(a + b) / 2 ]^2 - [(a - b) / 2 ]^2 = [( a + b +a - b )/ 2 ] x [ ( a + b - a + b )/ 2 ]

=2a/2 x 2b/2 = ab
therefore, BF=(ab)^(1/2)

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ANSHU KUMAR  (8 years ago)

Sorry.. My above ans. Is wrong..its a calculation mistake.. √ab*BC will be ans.
BF2= OF2-OB2 will be equation...

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gaurav kumar  (8 years ago)

Ans is: sqrt(AB*BC)

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ANSHU KUMAR  (8 years ago)

Ans.√ab2+bc2/2
We know that diameter =ab+be
Let ab=x and be=y
Radius=x+y/2
SO, OF =X+Y/2
and OB=OE-BE
Now, OF2=OB2+BF2
by putting all value and by solving above
We get bf = √ab2+bc2/2

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Ayush  (8 years ago)

length of BF is always in seconds,minute or hour if si unit is considered then in second.
please specify the site from which you downloaded the BF ie from brazzers or naughty america etc.

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jojo  (8 years ago)

the answer to this question is sqrt(AB*BC)

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DEEPAK RAJ  (8 years ago)

Please explain. I had also the same ques.

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Anjai Baghel  (8 years ago)

x, y sides of rectangle AB=x and BC=y
Ab is produced to E such that BC= BE THEN BE=Y
AE as a diameter which we can represent as AB+BE= x+y
Now circle is drawn with AE as diameter
Now n is a point on line AE so when BC produced to meet the circumference of circle to point F, SO BF is a radius of circle so BF=x+y/2

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kundan prasad  (8 years ago)

Ans:BF=AB
Sol: Diameter =>AB+BE= CB+BF (given that BC=BE )
So therefore AB=BF

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aayush  (8 years ago)

take length of rectngle=l, breath=b
now radis of circle=(l+b)/2. so of =(l+b)/2, trangle obf is right trngle
so,sqrt(of^2-ob^2)=bf
now bf -bc=cf

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nashrah  (7 years ago)

how bf is a radius of circle itz not given specifically that b is originating from center

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sangeeta kumari  (6 years ago)

@ Jignesh Mishty don't to know how to talk to a girl!Even if Anjali is answering wrong ,no one gave u any right to act like a barbarian!It shows what ur level is ,you are a SAVAGE.Learn to be a decent and sophisticated guy!learn manners

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Ayush Barnawal  (6 years ago)

check this out:-
http://www.logicguns.com/q/abcd-is-a-rectangle-side-ab-is-produced-to-e-such-that-bcbe-a-circle-is-drawn-with-ae-as-diameter-the-line-bc-is-produced-to-meet-the-circumference-of/5617da0a2b78726726a8a320/

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