Latest Elitmus Aptitude Question SOLUTION: ln(e(e(e......)1/3)1/3)1/3 here 1/3 is power of each bracket 1. 0 2. 1/2 3. 1 4. not remember

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Log and Antilog

Elitmus Question Papers:

(#M40152540) ELITMUS Numerical Ability question apti Keep an EYE

ln(e(e(e......)1/3)1/3)1/3
here 1/3 is power of each bracket
1. 0
2. 1/2
3. 1
4. not remember

Asked In Elitmus raksha singh (8 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (0)   (1) Submit Your Solution Log and Antilog

Read Solution (5) :

vishal  (8 years ago)

1/3/1-1/3===>1/2

Is this solution Helpfull? Yes (2) | No   

ashish pathak  (8 years ago)

it's simple man it is gp
like 1/3+1/9+1/27...........................................................infinite
so now
(1/3)/(1-1/3)=1/2

Is this solution Helpfull? Yes | No   

Nikhil   (8 years ago)

(1/3)/(1-1/3)====1/2

Is this solution Helpfull? Yes | No (1)  

Poonam  (8 years ago)

4th option was 1/3.

Is this solution Helpfull? Yes | No   

kundan prasad  (8 years ago)

Ans: 2) 1/2
Sol: Let y =(e(e(e.........)^1/3)^1/3)^1/3
y^3=e(e(e......)^1/3)^1/3
y^3=e(e(e........)^1/3)^1/3
y^3=e(y)
y(y^2-e)=0
y=0,sqroot(e),-sqroot(e) (we chose only positive value i,e sqroot(e))
y=sqroot(e)
hence ln(e)^1/2
2*lne=2*1=2

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.