Latest Elitmus Aptitude Question SOLUTION: A X M L M P -------------------------- V M S W V F M X X V S A -------------------------- V F F W L W

as M*M=X
possible values of X={1,4,5,6,9 }
put the values and try to find the values of 2nd row one by one
u will find X=4 at M=8 satisfy the conditions


648
789
................
5832
5184
4536
............................
511272

x+1=v
m*m=x
s+x=l
m* p=w
................soln....
x=m*m
m!= 0,1,5,6(when these digit multiply with itself digit ..it will give same digit so this is not possible
possible value for m=2,3,4,7,8,9
possible value for x=4,9,16,49,64,81(accord m )
2v+1=f;
x+1=v
x not be 9 because when 1 is add with 9 it will give 10 but v is single .
x=(4,9,16,49,64,81)
x is not possible 49,9;
now possible value for x=(4,16,64,81)
possible value of m =(2,4,8,9)
x+1=v;
possible value of v = (5,7,5,2) no is 2 digit we take unit place digit ;
2v+c1=1f (c1 is carry and when this is added to 2v it also generate carry )
possible value of v :
2v + c1= 1f ( carry may be 1 or mxm 2)
v=2; 2*2+1=5(if c1 =1)
v=2 ;2*2+2=6(if c1 =2)
this value is not possible value of v bc it generate 2 digit no
possible value of v =(5,5,7)
possible value of x=(4,4,6)
possible value of m=(8,2,4)
v+f+s+c2=f
it possible when
v+s+c2=10;(c2 is carry it may be 1 or maxm 2)
v=5 + s=4 + c2=1 =10
v=5 + s=3 + c2=2=10( valu s put accord to v and s )
v=4 + s=5 +c2 =1= 10 ( accord to this ,value of x = 3 , which is not possible )
v=4 + s=4 + c2=2 = 10( value not possible bc v and s are equal )
now

possible value of v = 5
possible value of s =3,
possible value of x =4
possible value of m = 2,8;

s+x=l
3+4 =7
m*l=_a
(2,8)* 7=(14,56)
POSSIBle value of a =(6, bc 14 is not possible we always take unit digit but unit digit is 4 it is equal to x )
m= 8;

a*l=x
a*7=4( possible value of a = 6 , when multiply it give 42 and it in right side so we take 10 digit no ==4 )

m= 8
v=5
s= 3
x=4
a=6
p=9;
other value u can find easily ....
i hope you will understand

M=(2,3,4,7,8,9)
Since M*M= X
and X+1= V
so possible value of X should be
X= 4,6,9
Hence possible value of V =5,7
Because at X= 9 , V= 0 this is not possible
So
Case 1- when X=4 then V=5 and M can be 2or 8
By calculation you will find that at X=4 ,V=5 and M = 8 is satisfying the condition of second row
Hence
648
789
........
5832
5184
4536
..........
511272

648
789
........
5832
5184
4536
..........
511272

as M*M=X
possible values of X={1,4,5,6,9 }
put the values and try to find the values of 2nd row one by one
u will find X=4 at M=8 satisfy the conditions


648
789
................
5832
5184
4536
............................
511272

648
789
------
5832
5184-
4536--
----------
511272

as V+V+C=F means v should be more than 5 so trail and error (v=5,6,7,8,9) but unluckily v=5

648
789
.......
5832
5184
4536
............
511272

Do they Provide options???

how 648 came

648*789
-------------
5832
5184
4536
---------
511272

Solution:

AXM
LMP
............
VMSW
VFMX
XVSA
..............
VFFWLW

1.first see x+1=v.
2.Then check all the possibility for RM*M=MR.
if u did step 2 properly then u see, u are completed this problem 20 or 30%. because this time u know the value of X=4 so then v=5, M=8, p=9.
3.solve A48*8 = 5F84. try all possibility and u found F=1;
4.Solve 5+1+s = _1. then u found s=3.
5.Solve A48*8=5184. then u found a=6 and by solving M+M+A=w (8+8+6=2). that means w=2.
6.Solve 648*P=5832. Then u also found value of p=9.

so U got like this
648
* 789
--------------
5832
5184-
4536--
---------------
511272
---------------

Try solving by spliting like this:
AXM*L=XVSA
AXM*M=VFMX (start solving from this, easily can be evaluated)
AXM*P=VMSW

648
789
---------
5832
5184
4536
------------
511272

a=6,x=4,m=8,l=7,p=9,v=5,s=3w=2,f=1