Latest TCS Aptitude Question SOLUTION: a. 3.1035*10˄64 b. 2.1021*10˄65 c. 3.1035*10˄63 d. 3.1035*10˄62

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(#M40153143) TCS Numerical Ability question 1) 1!+2!+3!+……………………………..+50!=? Keep an EYE

a. 3.1035*10˄64
b. 2.1021*10˄65
c. 3.1035*10˄63
d. 3.1035*10˄62

Asked In TCS Rajashekar (8 years ago)

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SAMARPAN BISWAS  (8 years ago)

3.1035*10˄64

Common Sum. Memorize the answer.

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Diptabhas Chakraborty  (8 years ago)

he least significant digits can be calculated, because they remain fixed! Starting at 1!+2!+3!+4! = 33, the units digit will remain 3 indefinitely. The sum at 9! will have the fixed last two digits (10! ends with two 0s).

The most signigicant digits can be found in a similar way, pretty much done above, with 50! having the same leading digit as S. So
S = 3. something...3 x 10^64

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swathi choda  (8 years ago)

option 1 i think so....

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