Latest Elitmus Aptitude Question SOLUTION: he Range of the function f(x) = (x - 2) / (2 - x) is A) -1 to 1 B) 0 to 1 C) -1 to 0 D) None of above Asked In Elitmus Read more at http://www.m4maths.com/placement-puzzles.php?S

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(#M40153792) ELITMUS Numerical Ability question apti Keep an EYE

he Range of the function f(x) = (x - 2) / (2 - x) is
A) -1 to 1
B) 0 to 1
C) -1 to 0
D) None of above

Asked In Elitmus

Read more at http://www.m4maths.com/placement-puzzles.php?SOURCE=Elitmus#ilJaJa2gfHCp2BTL.99

Asked In Elitmus SNIGDHA RANI SAHOO (8 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

dytort  (8 years ago)

-1 to 0

f(2) = (2 - 2)/(2 - 2) = 0/0 = 0
f(1) = (1 - 2)/(2 - 1) = -1/1 = 1

Is this solution Helpfull? Yes (6) | No (7)  

Rishabh Kant Jha  (8 years ago)

D) NONE Of THESE

f(x) = 2-x/x-2 = (2-x)(2-x)/(x-2)(2-x) = (2-x)^2 / (-1) (2-x)^2 = -1

so , right answer is -1.

Is this solution Helpfull? Yes (5) | No (1)  

SOUMYADIP MITRA  (8 years ago)

f(x)=(x-2)/(2-x)
for x=-1, f(-1)=-1; for x=0, f(0)=-1;
for x=-2,f(-2)=-1; for x=1,f(1)=-1;
similarly for all negative values of x f(x)=-1; similarly for all positive values of x the output will be -1 except at x=2 the value is undefined;
so the range of f(x) "-∞ to +1 and +3 to +∞"
answer is D. None of The Above

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deshraj  (8 years ago)

D) because -(2-x)/(2-x)=-1
-1 is constant which is independent of x, so range is -1.

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veerabhadra  (8 years ago)

SoLution pls

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ANUP KUMAR  (8 years ago)

d. None of these

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Niraj Kumar  (8 years ago)

f(x)=(2-x)/(x-2)=-1
f(x) is a constant function ..its range is -1,when x!=2

Is this solution Helpfull? Yes | No (1)  

SANTU MAITY  (8 years ago)

f(x)=(x-2)/(2-x)
where,x=0,+-1,+-2,+-3,...infinite
x=0,f(x)=-1, x=1,f(x)=-1, x=-1,f(x)=-1, x=2,f(x)=0, x=-2,f(x)=-1, x=3,f(x)=-1, x=-3,f(x)=-1
therefor, this is the ans option C

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