Latest Elitmus Aptitude Question SOLUTION: if v,w,x,y,z are non negative integer, each less than 11,then how many distinct combinations(w,v,x,y,z) satisfy v(11^4)+w(11^3)+x(11^2)+y(11)+z=151001. optn a)0 b)1 c)2 d)3

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(#M40153808) ELITMUS Numerical Ability question quant Keep an EYE

if v,w,x,y,z are non negative integer, each less than 11,then how many distinct combinations(w,v,x,y,z) satisfy v(11^4)+w(11^3)+x(11^2)+y(11)+z=151001.
optn
a)0
b)1
c)2
d)3

Asked In Elitmus sukriti singh (8 years ago)

Unsolved Read Solution (8)

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Santosh Uplawdiya  (8 years ago)

151001 / 11^4 = 10 with remainder = 4591

4591 / 11^3 = 3 with remainder = 598

598 / 11^2 = 4 with remainder = 114

114 / 11^1 = 10 with remainder = 4

Therefore 151001=10(11^4)+3(11^3)+4(11^2)+10(11^1)+4

i.e., (v,w,x,y,z) is (10,3,4,10,4). These values satisfies given conditions and is one valid option.

Let's analyze if further option available satisfying the given condition. v,w,x,y,z should be less than 11 and greater than zero. The solution we got have v as 10. Suppose v=9. With this, the maximum value possible under the given constraints is
9(11^4)+10(11^3)+10(11^2)+10(11^1)+10=146409

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Santosh Uplawdiya  (8 years ago)

So Ans is B) = 1 Only.

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Santosh Uplawdiya  (8 years ago)

Remaining solution...

Let's analyze if further option available satisfying the given condition. v,w,x,y,z should be less than 11 and greater than zero. The solution we got have v as 10. Suppose v=9. With this, the maximum value possible under the given constraints is

9(11^4)+10(11^3)+10(11^2)+10(11^1)+10=146409

Is this solution Helpfull? Yes (1) | No   

Santosh Uplawdiya  (8 years ago)

..
9(11^4)+10(11^3)+10(11^2)+10(11^1)+10=146409

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koushik  (8 years ago)

v(11^4)+w(11^3)+x(11^2)+y(11)+z=151001

151001/11 gives remainder 4.

v(11^4)+w(11^3)+x(11^2)+y(11) = 151001 - z
to make it divisible by 11, z should be 4..
as value of z cannot be any other number, we can form only on 1 distinct combination..
Answer is (B)-1

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narsingh patel  (8 years ago)

ans is b only

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chandan kumar mania  (8 years ago)

I am sorry to say that your question was wrong. Because there is no mention area, perimeter....

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SANTU MAITY  (8 years ago)

v(11^4)+w(11^3)+x(11^2)+y(11)+z=151001=11*13727+4
therefore, z=4,next
11*v(11^3)+11*w(11^2)+11*x(11^1)+y(11)=11*13727
11*v(11^2)+11*w(11^1)+11*x+y=13727=11*1247+10
where,y=10,then
11*v(11^1)+11*w+x=1247=11*113+4
where,x=4,then
11*v+w=113=11*10+3
where,w=3,then
11*v=11*10
then,v=10
therefor,z=4,y=10,x=4,w=3,v=10,
ans is 3.

Is this solution Helpfull? Yes | No (1)  

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