Latest Elitmus Aptitude Question SOLUTION: is x>y 1. 5x+15y=40 2.7x+21y=56 data sufficency elitumus question

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(#M40153896) ELITMUS Category question data sufficency Keep an EYE

is x>y
1. 5x+15y=40
2.7x+21y=56
data sufficency elitumus question

Asked In Elitmus Kundan singh (8 years ago)

Unsolved Read Solution (9)

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Amit Bansal  (8 years ago)

Answer (d)
infinite solutions so cant be determined

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Deepak Gupta  (8 years ago)

both lines are parallel .......ans (d)....we can't answer even using both the stmt
if u multiply first 1 with 7 and second with 5 then you will find 0 after subtracting them

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Vikas Jha  (8 years ago)

Since there's two variables and two equation so.. both 1) and 2) are required to answer.

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abhilash chhipa  (8 years ago)

@vikas jha
see both equations..both are same x+3y=8
so we cant solve
and it is also true for x=y=2
so ans will be (d)

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Anjan Chowdhury  (8 years ago)

only one is required either 1 or 2
x=5,y=1
because x>y

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Vikas Jha  (8 years ago)

Yep.. Sorry that was my mistake. Can't be determined even using both the equation.

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subhajit Roy   (8 years ago)

ans (b)
for condition I
5x+15y=40 if y=0 than x=8
if x-9 than y=8/3
in same way for condition II
X=8 and Y=8/3

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Rakesh  (8 years ago)

both equation are same.
2nd equation is 1.4 times of 1st equation.
thus can't be determined using both equation.

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Amit Sankhyan  (8 years ago)

I don't know why you all guys started to find the exact value of X and Y, & hence gave wrong answers.
The question asks for whether, X > Y, which means is it TRUE or FALSE.
So 1st alone is sufficient (2nd is identical to first) to answer the question. Put any value, X will always be greater than Y.

For 1st equation
Zero values:: x= 0, y = 40/15 ; y=0, x= 5 . => x >y
Positive values:: x=1, y = 35/15 ; y=1 , x=5 => x> y
negative values:: x=-1, y = 3 ; y=-1 , x= 11 => x>y

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