Latest Elitmus Aptitude Question SOLUTION: In a right angled triangle, two sides are consecutive whole number in which one side is hypotenuse. what could be the possible length of third side?

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Geometry

Elitmus Question Papers:

(#M40153914) ELITMUS Numerical Ability question Geometry 27/09/2015 Keep an EYE

In a right angled triangle, two sides are consecutive whole number in which one side is hypotenuse. what could be the possible length of third side?

Asked In Elitmus Abhinav Akash (8 years ago)

Unsolved Read Solution (15)

Is this Puzzle helpful?   (9)   (2) Submit Your Solution Geometry

Read Solution (15) :

mohit  (8 years ago)

Options were 360, 361, 362 , none of these..
I think answer will be 361

Is this solution Helpfull? Yes (10) | No (5)  

Kumar Gaurav  (8 years ago)

Hypotenuse=5 , Second side= 4;
so the third side could be 3

Is this solution Helpfull? Yes (9) | No   

SHUBHAM  (7 years ago)

watch it
https://www.youtube.com/watch?v=86YAPbZmsRI

Is this solution Helpfull? Yes (7) | No   

kumar mohit  (8 years ago)

basically triplet are 3,4,5,
5,12 ,13
7,24,25,
8,15,17.....question on consecutive whole number so 3,4,5
we can multiply any digit (digit >0 ) .that will also triplet ..
ex 30,40,50
45,60,75,
300,400,500

Is this solution Helpfull? Yes (5) | No (1)  

James Anderson  (7 years ago)

Pythagorean triplets are generated with each "odd number" greater than 1 by using a formula.
If n is an odd number, then Pythagorean triplet = n,n2−12,n2+12.
Here 361 is an odd number. So the triplet is 361, 65160, 65161.
so answer is 361

Is this solution Helpfull? Yes (4) | No   

Sonu kumar  (8 years ago)

option are 1.360 2.361 3.361 4.none of these

correct answer is 2.361

(361)^2 + x^2=(x+1)^2
you solve this u get the answer.

Is this solution Helpfull? Yes (2) | No (3)  

ananga  (8 years ago)

triplet 3,4,5 satisfing da condition
hypotenus is 5 (given)
so another side 4
and the 3rd side must be multiple of 3...
now choose from the options.

Is this solution Helpfull? Yes (2) | No   

SANTU MAITY  (8 years ago)

options were 360,361,362,none of these..
answer...none these
y^2+x^2=(x+1)^2
y^2=2x+1
(y,x)=(3,4),(5,12),(7,24),(9,40).........(25,312),(27,364)....

Is this solution Helpfull? Yes (2) | No   

Archit Agarwal  (7 years ago)

(x+1)--> hypotenuse
x--> base
h--> height

x^2 + h^2 = (x+1)^2
x^2 + h^2 = x^2 + 1 + 2x
h^2 = 1 + 2x

now put the value given in the option in place of h,
the value of h that give the whole no. value of x is the right answer
i.e 361

Is this solution Helpfull? Yes (2) | No   

Lalit Garg  (8 years ago)

It should be every odd number except length of 1.

Is this solution Helpfull? Yes (1) | No (1)  

ankit  (8 years ago)

In a Right angle triangle the triplets are of form 2m, 2m-1, 2m+1.
where the hypotenuse is 2m+1, so other side would be 2m or 2m-1.
for example m=2, hypotenuse will be 5 and other sides would be 4,3.

Is this solution Helpfull? Yes | No   

chaitalibanerjee  (8 years ago)

Plzz xpln y d ans is 361 mns how???

Is this solution Helpfull? Yes | No   

Tuhin Barai  (8 years ago)

If one of the side is A and hyp is B then the thirsd side is always Root Over A+B. Take 4 and 3 Third side will be root 7 and likewise.. .. ...

Is this solution Helpfull? Yes | No (1)  

yugal kishore sinha  (7 years ago)

13^2=12^2+5^2

Is this solution Helpfull? Yes | No   

Madhu  (6 years ago)

Pythagorean triplets are generated with each "odd number" greater than 1 by using a formula.
If n is an odd number, then Pythagorean triplet =
n
,
n
2
−
1
2
,
n
2
+
1
2
n,n2−12,n2+12.
Here 361 is an odd number. So the triplet is 361, 65160, 65161.

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.