Latest Elitmus Aptitude Question SOLUTION: 16 +17+18+19=70. How many such 4 consecutive numbers are there less than 1000 when added gives a sum which is divisible by 10?

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(#M40154105) ELITMUS Numerical Ability question 4 digit sum Keep an EYE

16 +17+18+19=70. How many such 4 consecutive numbers are there less than 1000 when added gives a sum which is divisible by 10?

Asked In Elitmus Vaithiyanaathan (8 years ago)

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Read Solution (7) :

ian soklov  (8 years ago)

ans will be 200..
since 1+2+3+4=10 & 6+7+8+9=30
any combination with these no be will give u desirable result...
so total no in 100 will be 20 & that's why in in 1000,it will be 200

Is this solution Helpfull? Yes (20) | No (2)  

Shyam Bihari Sharma  (8 years ago)

Ans will be 200

1. 1+2+3+4=10
2. 6+7+8+9=30
3. 11+12+13+14=50
4. 16+17+18+19=70
....
.....
.....
20. 96+97+98+99=390

so from 1 to 100 total nos will be 20

then finally 1 to 1000 nos will be 20*10==200

Is this solution Helpfull? Yes (13) | No (1)  

Mayank   (8 years ago)

Ans is : 200
From 1 to 10 there are 2 pairs (1+2+3+4=_0 & 6+7+8+9=_0)
So, from 1 to 100 there are 20 pairs
Hence from 1 to 1000 there will be 20*10=200 such pairs

Is this solution Helpfull? Yes (5) | No   

NAVEEN KUMAR  (8 years ago)

1,2,3,4
6,7,8,9.........996,997,998,999

a+(n-1)d=996
=>1+(n-1)5=996
=>n=200

Is this solution Helpfull? Yes (4) | No   

Astik Suhane  (8 years ago)

ans. will be 200.......


because four consecutive no. is
5n+1, 5n+2. 5n+3, 5n+4....

so we can put 0 to 199 no in these four consecutive no...

if we are put 1 in 5n+1 then we will get 6

2 then 7,, 3 then 8 and 4 then 9 so we are add these four consecutive no.. 6+7+8+9=30
similarly 0 to 199 we can put ... which is less then 1000

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Dibyashree  (8 years ago)

For every 10 there are 8 nos so for every 100 there are 800 nos n for every thousand there are 8000 nos. So total 8000 nos are there for which each 4 consiqutive nos make a no divisible by 10

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ashutosh mishra  (7 years ago)

let us assume that 4 consecutive no. a,a+1,a+2,a+4
a+a+1+a+2+a+3=10*y
a=(10*y-6)/4
a must be divided by 4
a=1,3,5,7,.......................
1+(n-1)*2=999
n=500

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