Latest Elitmus Aptitude Question SOLUTION: root X+3=X root X+3 how many solution???

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Number System

Elitmus Question Papers:

(#M40154195) ELITMUS Numerical Ability question number system Keep an EYE

root X+3=X root X+3 how many solution???

Asked In Elitmus parul sharma (8 years ago)

Unsolved Read Solution (17)

Is this Puzzle helpful?   (2)   (2) Submit Your Solution Number System

Read Solution (17) :

MANISH KUMAR  (8 years ago)

root(x+3)=x root(x+3)
=>square both side
=>x+3=x2(x+3)
=>(x+3)(x2-1)
=>(x+3)(x+1)(x-1)
hence 3 solution is there

Is this solution Helpfull? Yes (22) | No (16)  

Dibyashree  (8 years ago)

(X root x+3)- (root x+3)=0
solutions are two
1,-3

Is this solution Helpfull? Yes (17) | No (5)  

akanksha srivastava  (8 years ago)

it has three solutions (1,-1,-3)
Solution:
firstly squaring on both sides we get
(X+3)=X^2(X+3)
X^3+3(X^2)-X-3=0
on simplifying this equation we get
(X-1)((X^2)+4X+3)
on solving this we get
(X-1)(X+1)(X+3) Ans. 1,-1,-3 so three solution

Is this solution Helpfull? Yes (10) | No (5)  

umesh  (8 years ago)

Given
root(x+3)=x root(x+3)---------------(1)
=> Taking square both side
=>x+3=x(x+3)^1/2
=>(x+3)(x^2-1)
=>(x+3)(x+1)(x-1)
now check for each values values in the eq.1
for x=-3 =>0=-3*0
0=0 possible one sol.
for x=-1 =>(-1+3)^1/2=-1*(-1+3)^1/2
root 2=-root 2 not possible
for x=-1 =>(1+3)^1/2=1*(1+3)^1/2
2=2 possible 2nd sol.

so total 2 solutions are possible

Is this solution Helpfull? Yes (9) | No (3)  

shivani  (8 years ago)

1 solution bec root x+3 cancel and only 1 value is possible

Is this solution Helpfull? Yes (7) | No (6)  

RANJAN FADIA  (8 years ago)

only one solution
since x=1 is satisfying above condition

Is this solution Helpfull? Yes (5) | No (3)  

RAKESH RANJAN  (8 years ago)

it has three solutions (1,-1,-3)
Solution:
firstly squaring on both sides we get
(X+3)=X^2(X+3)
X^3+3(X^2)-X-3=0
on simplifying this equation we get
(X-1)((X^2)+4X+3)
on solving this we get
(X-1)(X+1)(X+3) Ans. 1,-1,-3 so three solution

Is this solution Helpfull? Yes (3) | No (4)  

Rahul KUMAR  (8 years ago)

there will two solution if we square both the side of equation.
-1 & +1 so there is definitely 2 solution.
here options are not given. so i can't say the correct ans

Is this solution Helpfull? Yes (2) | No (4)  

jaya dwivedi  (8 years ago)

root of(x+3)=x root of(x+3)
square both side
root(x+3)^2=[x root(x+3)]^2
x+3=x^2*(x+3)
(x+3)divided by (x+3)=x^2
1=x^2
x=+1,-1
means two solution

Is this solution Helpfull? Yes (2) | No (3)  

MANJARI  (8 years ago)

2 solution.that is +1,-1

Is this solution Helpfull? Yes (1) | No   

anusha  (7 years ago)

When we are squaring both sides after finding out x we have to check whether LHS= RHS and if the condition satifies then the solution obtained is correct . In this case when we substitute X= -1 LHS# RHS and we have only 2 values for X

Is this solution Helpfull? Yes (1) | No   

Vikash kumar  (7 years ago)

the correct answer is 3
explanation:
root(x+3)-x root(x+3)=3
root(x+3)[1-x]=3 take root(x+3) is common
square both side
we get,
(x+3)(x-1)^2=9
we get 3 value of x.

Is this solution Helpfull? Yes (1) | No   

akash gupta  (8 years ago)

2 solution are possible
rootx(x-1)=0
x=1and x=0

Is this solution Helpfull? Yes | No (5)  

priyanka  (8 years ago)

Only one solution possible - 1

Is this solution Helpfull? Yes | No (2)  

Anuj singla  (8 years ago)

only one solution -3/2
=> x+3=x
square both sides, we get
=> x^2+6x+9=x^2
on simplifying it, we get
=> x= -3/2

Is this solution Helpfull? Yes | No (1)  

mohit shukla  (8 years ago)

@Naveen Kumar we can not take G=8 as 8 is already given in the same row and we know every variable has unique value so it violates the basic rule of crypto.

So look for the different values of G.

Is this solution Helpfull? Yes | No (2)  

Niharika Behera  (8 years ago)

Answer will be 0.
Because other than 0 root will not be zero

Is this solution Helpfull? Yes | No (2)  

Please Login to Read Solution.