Latest TCS Aptitude Question SOLUTION: .the tcs office at siruseri is at a distance of 21km from baburaj’s home.when he leaves home 10 minutes late his travel time increases by 40% if leaving late decreases his averag

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(#M40154805) TCS Numerical Ability question Keep an EYE

.the tcs office at siruseri is at a distance of 21km from baburaj’s home.when he leaves home 10 minutes late his travel time increases by 40% if leaving late decreases his average speed by 12kmph how long does his commute take when he leaves on time a)1 hour b)21minutes c)30 minutes d)40 minutes

Asked In TCS anindita (8 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

Sharanyu Ghosh  (8 years ago)

Let his travel time be 'x' when he leaves for his office on time.
When he leaves home 10 minutes late his travel time becomes (x+(40/100)*x) which is equal to (7x/5).
Therefore,His speed when he leaves home 10 minutes late=(21)divided by(7x/5)=15/x.
His average speed when he leaves on time=21/x.
According to the question,
(15/x)=(21/x)-12
Solving the above equation, we get x=(1/2) hour=30 minutes.

Is this solution Helpfull? Yes (12) | No (2)  

Karthika  (8 years ago)

When he starts at right time travel time=t
When he starts at 10 min late travel time=1.4t
21/t - 21/1.4t =12
Solving we get t=1/2=30 min

Is this solution Helpfull? Yes (11) | No   

manikandan  (8 years ago)

S*t=21;
S-12*(1.4t+10/60)=21;...try solving this using options convert mins to hrs ...ie if 20 mins then 20/60..try to solve u ll find ans as 40/60 ie 40mins

Is this solution Helpfull? Yes (4) | No (5)  

Ayush  (8 years ago)

Let time taken by him when he leaves on right time = t
and average speed will be 21/t

then time taken by him when he leaves 10 min late = 1.4t
and average speed = 21/t-12

distance is constant so , 21/t*t = 1.4t/10(21/t-12)

solving the above eq.we get t= 0.5 hr or 30 minutes

Is this solution Helpfull? Yes (3) | No (1)  

Prajukta Chatterjee  (8 years ago)

time=30mins

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alka acharjya  (8 years ago)

@prajukta can u plz explain....
Regards

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manikandan  (8 years ago)

S=d/t;S= 21*3/2=31.5-->1
31.5-12*(1.4*40/60+10/60)..solving this you ll get approx 21.45 which is more or less equal to 21..

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pk  (8 years ago)

(C) - 30 is the answer.

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manikandan  (8 years ago)

In d same case you are telln 30 mins where that 10 mins in the que went away??

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