Latest TCS Aptitude Question SOLUTION: 123412344123444123444412344444... now the last two terms of 200th number

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(#M40154957) TCS Numerical Ability question Keep an EYE

123412344123444123444412344444... now the last two terms of 200th number

Asked In TCS Malaya Prasad Lenka (8 years ago)

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Malaya Prasad Lenka  (8 years ago)

Here in this question 1234123441234441234444....
Here after 123 the no of 4s varies arithmetically so no of 4s varies directly to the no of 123s before it.
Suppose i take 17 4s at end .
So total 4s in it is 17*18/2=153.
Now 123 pairs = 17 so total nos =17*3=51+153=204
Now subtract 4 from these . Still 13 4s .
So last 2 digits are 44.
Hope it is the right one .
come with another one if any.

Is this solution Helpfull? Yes (18) | No (2)  

akhil john  (8 years ago)

441....I THINK SO

Is this solution Helpfull? Yes (4) | No (4)  

tany  (8 years ago)

1st 4 terms 1s - 1, 2s - 1, 3s - 1 4s - 1 = 4 = 4*1+0
1st 9 terms 1s - 2, 2s - 2, 3s - 2 4s - 3 = 9 = 4*2+1
1st 15 terms 1s - 3, 2s - 3, 3s - 3, 4s - 6 =15= 4*3+3
.
.
.
1st 188 terms 1s - 18, 2s - 18, 3s - 18 4s - 134 = 188 = 18*4 + 116

so till 188 terms its 4 then again 1234444444......
so last two terms of 200th number is 44

Is this solution Helpfull? Yes (3) | No (1)  

Gourav Kumar Pandey  (8 years ago)

1st group 1234 number of digit 4
2nd group 12344 number of digit 5
3rd group 1234444 number of digit 6
so at the end of each group there will be series of 4s.
So the answer is 44

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