Latest TCS Aptitude Question SOLUTION: if a(b+c)=33 b(c+a)=40 c(a+b)=49 then find abc options are 14 square root 33 84 122 cannot be founded using given data

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if a(b+c)=33
b(c+a)=40
c(a+b)=49
then find abc options are
14 square root 33
84
122
cannot be founded using given data

Asked In TCS sahil arora (8 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

Angad  (8 years ago)

a(b+c)=33
so a=11 or 3
b+c=11 or 3
c(a+b)=49
c=7
a+b=7
so a=3
and b=4
and c=7
abc=84

Is this solution Helpfull? Yes (17) | No (1)  

Binod Kumar  (8 years ago)

simple question just factorize given no
33= 3*11 = a(b+c)
40=8*5=b(c+a)
49=7*7=c(a+b)
from the last equation it is clear that c=7 which means b must be = 4 and a = 3
therefore a*b*c = 7*4*3= 84.

Is this solution Helpfull? Yes (7) | No (1)  

Priyesh jain  (8 years ago)

as given
ab+ac=33 …eq1
bc+ab=40…eq2
ac+bc=49.…eq3

than eq1-eq2
bc-ac=7…eq4

eq2-eq3
ac-ab=9 …eq5

eq3-eq1
bc-ab=16…eq6

now again
eq2+eq6
bc=28
eq1+eq5
ab=21
eq3+eq4
bc=28

but yet we did not get ab, so put the value of bc in eq2 and ab=12
now
ab*bc*ac=28*21*12
(abc)^2=7056
abc=84

Is this solution Helpfull? Yes (5) | No   

simarpreet   (8 years ago)

Put a=3,b=4,c=7
3(4+7)=33
4(7+3)=40
7(3+4)=409

So abc=3*4*7=84

Is this solution Helpfull? Yes (2) | No   

vinay agarwal  (8 years ago)

ANs......84
a(b+c)= 33 => ab+ac=33-------(i)
b(c+a)= 40 => bc+ab=40-------(ii)
c(a+b)= 49 => ac+bc=49-------(iii)

add above 3 eqn
2ab+2bc+2ac= 122
ab+ac+bc=61------(iv)

Now solve eqn(i) and eqn (iv) we will get bc=28
similarly ac=21 & ab=12

Now ab*ac*bc= 5761
abc= under root of 5761 that is 84

ANswer is 84

Is this solution Helpfull? Yes (1) | No   

nitin sharma  (8 years ago)

c(a+b)=49
factors of 49=7*7
c=7 and a+b=7
then
a(b+c)=33
factors of 33=3*11
so a=3 b=4 bcoz c=7
answer =3*4*7=84

Is this solution Helpfull? Yes | No   

sanjeev kumar  (8 years ago)

a(b+c)=33=3*11
b(c+a)=4*10
c(a+b)=7*7
a=3,b=4,c=7
so,a*b*c=3*4*7=84

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