Latest Elitmus Aptitude Question SOLUTION: 1.what is the maximum possible remainder when a number 104^n is divided by 51 ? (Assume n be any positive integer) (a)29 (b) 32 (c) 96 (d)96

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(#M40155143) ELITMUS Numerical Ability question no. system Keep an EYE

1.what is the maximum possible remainder when a number 104^n is divided by 51 ? (Assume n be any positive integer)

(a)29 (b) 32
(c) 96 (d)96

Asked In Elitmus shailesh kumar shashi (8 years ago)

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NAVEEN KUMAR  (8 years ago)

here is Sol URL---> http://postimg.org/image/3xvnp5b7d/

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sanjeet kumar  (8 years ago)

Ans (b)=32

let n=1 then 104/51= 2(rem)
for getting a max rem put n=5, because rem(2)*5= 32 which is less than 51

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Shagun Chaudhary  (8 years ago)

since 51×2=102
104-102=2
=>2^n will be the remainder
since n is a positive integer and viewing the options we can say that 32 is the only possible answer 😊

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NAVEEN KUMAR  (8 years ago)

Ans---b----32

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ANAMIKA KUMARI  (8 years ago)

(b)
unit place of (104)^n is either 4 or 6.
then when is divide by 51 then reminder having unit place will be either 2 or 4.
so here 32 will be answer....
for exam, n = 1, 104/51 reminder is 2.
but for n =2, 104*104/51 = 10816/51 reminder will be 4 and so on.....
so for proper answer, unit place of reminder should be either 2 or 4...

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ANKUSH SAXEN  (8 years ago)

ans is 171 naveen umar u forget to add these no. 110,220,330,440,550,660,770,880,990
162 + 9=171

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R VENKATESH REDDY  (8 years ago)

ans= (b)=32

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Anil Pokhariyal  (8 years ago)

ans is (b)

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MAHENDRA PATIDAR  (8 years ago)

naveen bhai thank u for upload image

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