Latest Elitmus Aptitude Question SOLUTION: The digital sum of no is given as 1994 ie [1+9+9+4 = 23 then 2+3 =5] unless we get a unit digit, Find the number of perfect squares obtained in the digital sum from 2000 to 2199 o

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(#M40155479) ELITMUS Numerical Ability question Digital Sum Keep an EYE

The digital sum of no is given as 1994 ie [1+9+9+4 = 23 then 2+3 =5]
unless we get a unit digit,
Find the number of perfect squares obtained in the digital sum from 2000 to 2199

optns r
22 42 16 nd may be d optns may be wrong but d ques is same

Asked In Elitmus Shashank Saha (8 years ago)

Solved Tanvi Jain Read Solution (9)

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Tanvi Jain  (8 years ago) Best Solution

Ans is 66
There are only 3 single digit perfect square i.e. 1,4,9
Total no. =200(including 2000 and 2199)

when we sum 2000=2+0+0+0=2
2001=2+0+0+1=3
2002=2+0+0+2=4 and upto
2199=2+1+9+9=21=2+1=3

we see a pattern no. are going from 2,3,4---9,1,2and so on

So no. of times pattern followed= 200/9=22 and 2 as remainder
So xcept 2 and 3 each no. will come 22 times
So total no. of times=22+22+22=66

Is this solution Helpfull? Yes (6) | No (2)  

BEDANGA BIKASH ROY MEDHI  (8 years ago)

given 2000 and 2199 then if we start adding the digits from start i.e 2000 and proceed a sequence is produced i.e difference of 5 and 4

here it goes

2002= 2+0+0+2=4(perfect square)
now

(2002) + 5 = 2007
taking 2007= 2+0+0+7=9(perfect square)

now add +4 to 2007= 2011 which is 2+0+1+1=4(perfect square again)

proceed this way...

Is this solution Helpfull? Yes (2) | No (2)  

nitin chauhan  (8 years ago)

we have to find that how many times the number which are perfect square by following digital sum rule occurs in the series 2000 to 2199

Total no. =200(including 2000 and 2199)

when we sum 2000=2+0+0+0=2
2001=2+0+0+1=3
2002=2+0+0+2=4 and upto
2199=2+1+9+9=21=2+1=3

we see a pattern no. are going from 2,3,4,5,6,7,8,9,1,2and so on
There are only 2 single digit perfect square i.e. 4,9
200/9=22 reminder as 2
so 22+22=44

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Rizul  (8 years ago)

44 is the correct answer

Is this solution Helpfull? Yes (1) | No (3)  

roushan raj  (8 years ago)

but 31 and 26 are given option there.........
what should be the?........

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Nikita goel  (8 years ago)

66.....after doing addition using digital method i.e 2+0+0+0=2
2+0+0+1=3
.......
.....
2+1+9+9=3
....so the number starts from 2,3,4...9,1,2,......9.....1,2,3
for perfect square only 1,4,9 are there...so 2+64=66

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prakash  (8 years ago)

d.66 s the total no

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Shashank Saha  (8 years ago)

GuySs how to determine dat
any formula involved

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catherine  (8 years ago)

as digital sum is single digit there are two possibilities either 4 or 9 i.e the sum of digits turn out to be 4 or 9.
now, the maximum sum of digits can be 2+1+9+9= 21.

So , we have to count all numbers whose sum of digits can be 4 or 9 (under the constraint that sum

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