Latest Elitmus Aptitude Question SOLUTION: Maximum value of N for {(100^8)-(111112^2)} is divisible by 3^N. What will be maximum value for N? (a)6 (b)2 (c)1 (d)0

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(#M40156094) ELITMUS Numerical Ability question Number System Keep an EYE

Maximum value of N for {(100^8)-(111112^2)} is divisible by 3^N. What will be maximum value for N?
(a)6
(b)2
(c)1
(d)0

Asked In Elitmus Dhrub Singh (8 years ago)

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