Latest Bank Exam Aptitude Question SOLUTION: out of 7 consonant and 4 vowels, how many words of 3 consonant and 2 vowels can be formed? ans:25200 please someone explain this

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(#M40156331) BANK EXAM Numerical Ability question permutation and combination Keep an EYE

out of 7 consonant and 4 vowels, how many words of 3 consonant and 2 vowels can be formed?

ans:25200

please someone explain this

Asked In Bank Exam krunal patel (8 years ago)

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Manisha Sadhu  (8 years ago)

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)

= inline {color{Black}(7C_3{}times 4C_2{})}

= 210.

Number of groups, each having 3 consonants and 2 vowels = 210.

Each group contains 5 letters.

Number of ways of arranging 5 letters among themselves

= 5!

= 120

Required number of ways = (210 x 120) = 25200.

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DURGESH YADAV  (8 years ago)

to select 3 cons and 2 vow is =7c3 x 4c2=35 x 6
now there are 5 letter which can be arrange as= !5=120
so total prob is =120 x 35 x 6=25200

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