Latest TCS Aptitude Question SOLUTION: Let a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127. What is a + b + c + d

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Number System

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40157264) TCS Numerical Ability question math Keep an EYE

Let a, b, c, d and e be distinct integers in ascending order such that(76-a)(76-b)(76-c)(76-d)(76-e) = 1127. What is a + b + c + d

Asked In TCS jayshree salunkhe (7 years ago)

Unsolved Read Solution (7)

Is this Puzzle helpful?   (29)   (7) Submit Your Solution Number System

Read Solution (7) :

Shubham Sanjay tarade  (7 years ago)

Product of 5 terms equal to 1127. As all the five terms are integers, given product should be a product of 5 numbers. Now factorize 1127.
1127 = 72 × 23 = 7 × 7 × 23
But given that all the a, b, c, d, e are distinct. And we are getting only 3 terms with 7 repeats.
Now the logic is, integers means positive and negative, 7 and - 7 possible and 1, - 1 also possible . As a,b, c, d, e are in ascending order, the factors should be in decreasing order. So (23, 7, 1, -1, -7)
Now a = 53; b = 69; c = 75; d = 77
a + b + c + d = 274.

Is this solution Helpfull? Yes (44) | No (10)  

Surbhi patel  (7 years ago)

M4maths.com you should provide correct and of each ques , because here people are answering with different different answers.

Is this solution Helpfull? Yes (19) | No (1)  

Saumajit Saha  (7 years ago)

1127=7*7*23
so we can say a=69
b=69
c=53
d=75
e=75
so that the product remains equal to 1127
so a+b+c+d = 69+69+53+75=266

Is this solution Helpfull? Yes (8) | No (31)  

akshay  (7 years ago)

 Product of 5 terms equal to 1127. As all the five terms are integers, given product should be a product of 5 numbers. Now factorize 1127. 1127 = 72 × 23 = 7 × 7 × 23 But given that all the a, b, c, d, e are distinct. And we are getting only 3 terms with 7 repeats. Now the logic is, integers means positive and negative, 7 and - 7 possible and 1, - 1 also possible . As a,b, c, d, e are in ascending order, the factors should be in decreasing order. So (23, 7, 1, -1, -7) Now a = 53; b = 69; c = 75; d = 77 a + b + c + d = 274.

Is this solution Helpfull? Yes (3) | No (1)  

navi chinnu  (7 years ago)

Product of 5 terms equal to 1127. As all the five terms are integers, given product should be a product of 5 numbers. Now factorize 1127.
1127 = 7 × 7 × 23
given that, a,b,c,d,e are distinct integers in ascending order.
so, (a,b,c,d,e) = (23,7,1,-1,-7)
then a+b+c+d = 274

If we don't consider the given statement, a,b,c,d,e are distinct integers in ascending order.
then (a,b,c,d,e) = (53,69,69,75,75)
then a+b+c+d = 266

Is this solution Helpfull? Yes (1) | No   

Debasish Roy  (7 years ago)

Factorisation of 1127 gives the possible values . Those are 1,-1,7,-7 and 23. on substitution we get a=53, b=69, c=75, d=77, e=83.

Is this solution Helpfull? Yes (1) | No (1)  

Surbhi patel  (7 years ago)

But Ascending order means Increasing order and you all are doing in Descending order why????

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.