Latest Elitmus Aptitude Question SOLUTION: A natural number has exactly 10 divisors including 1 and itself. How many distinct prime factors can a number have...? a. either 1 or 2 b. either 1 or 3 c. either 2 or 3 d. either

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(#M40158266) ELITMUS Numerical Ability question Number System Keep an EYE

A natural number has exactly 10 divisors including 1 and itself. How many distinct prime factors can a number have...?

a. either 1 or 2
b. either 1 or 3
c. either 2 or 3
d. either 1, 2 or 3

Asked In Elitmus Shashank Saha (7 years ago)

Unsolved Read Solution (6)

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Soumya Priyadarsini  (7 years ago)

ans is-either 1 or 2
Follow the link-http://www.m4maths.com/8864-a-natural-number-has-exactly-10-divisors-including-1-and-itself-how-many-distinct-prime-factors-can-this-natural-number.html

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neha  (7 years ago)

either 2 or 3 because 1 is not a prime number.

Is this solution Helpfull? Yes (1) | No (2)  

laxmi  (7 years ago)

ans is a.) either 1 or 2

B'z 1 is not prime no so we have only 9 divisor.
if we want to find the # of divisors of number so we take x^p1,y^p2 .... and so on
where x and y is prime factor and p1 and p2 is power.
so number of divisors =(p1+1) *(p2+1)
(p1+1) *(p2+1)=9
so we have only 3*3 means we have only 2 divisors or may be if p1=8 its means we have only one factors

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kamakshi gupta  (7 years ago)

either 2 or 3
eg; 10000

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Rishabh Dev Mittal  (7 years ago)

either 1 or 2

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Ayushee Bhardwaj  (6 years ago)

either 1or 2

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