Latest Elitmus Aptitude Question SOLUTION: (100)power 8-(111112) power 2 divide by 3 power n. find the maximum value of n. option : a) 3 b) 2 c) 1 d)0

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Number System

Elitmus Question Papers:

(#M40160100) ELITMUS Numerical Ability question quant Keep an EYE

(100)power 8-(111112) power 2 divide by 3 power n. find the maximum value of n.

option : a) 3
b) 2
c) 1
d)0

Asked In Elitmus Sahil Tanwar (7 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (0)   (3) Submit Your Solution Number System

Read Solution (5) :

Nidhi Gupta  (7 years ago)

since it is 100^8 converting it in the power of 2.
so 100^8=(100000000)^2
now,
100000000^2-111112^2 .'. a^2-b^2=(a+b)(a-b)
=(100000000-111112)(100000000+111112) =99888888*100111112

99888888*100111112 so 9+9+8+8+8+8+8+8=66 66 is divisible by 3 but not 9 so ans should be ->3^1

Is this solution Helpfull? Yes (8) | No   

Aachal Soni  (7 years ago)

n=1 ::(100111112)(99888888)/3^n . 99888888 is divisible by 3.so whole value is also divisible by 3.

Is this solution Helpfull? Yes (7) | No   

DEEPALI AGARWAL  (7 years ago)

since it is 100^8 converting it in the power of 2.
so 100^8=(100000000)^2
now,
100000000^2-111112^2 .'. a^2-b^2=(a+b)(a-b)
=(100000000-111112)(100000000+111112) =99888888*100111112=
trying to divide it by 9 and 3 subsequently we will get the value of n as 3.

Is this solution Helpfull? Yes (5) | No (6)  

alpha cube  (6 years ago)

100^8=(100000000)^2 - 111112^2=1222232 = 98777768
it is only divisible by 3^1 and not by 3^2 as the result is not following 9 divisiblty rule

Is this solution Helpfull? Yes (1) | No   

Pradosh kumar  (7 years ago)

are bhai explain the question please ????

Is this solution Helpfull? Yes | No (3)  

Please Login to Read Solution.