Latest Elitmus Aptitude Question SOLUTION: if v,w,x,y,z are non negative intergers each leass than 7,then how many distinct combinations are possible of(v,w,x,y,z) satisfy v(7^4) +w(7^3)+ x(7^2)+ y(7) +z=151001

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(#M40164379) ELITMUS Numerical Ability question Arthemetic Keep an EYE

if v,w,x,y,z are non negative intergers each leass than 7,then how many distinct combinations are possible of(v,w,x,y,z) satisfy v(7^4) +w(7^3)+ x(7^2)+ y(7) +z=151001

Asked In Elitmus Siva nagendra (7 years ago)

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kusuma kumari madapati  (6 years ago)

151001=62*7^4+6*7^3+0*7^2+0*7^1+1
v=62
w=6
x=0
y=0
z=1
only these combinations can produce the result
so unique solution

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JAYRAM DHAR DUBEY  (6 years ago)

Dividing 151001 by 11^4 give quotient 10 and remainder 4591

So

151001 = 10*11^4 + 4591

Dividing 4591 by 11^3 gives quotient 3 and remainder 598

So

151001 = 10*11^4 + 3*11^3 + 598

Dividing 598 by 11^2 gives quotient 4 and remainder 114

So

151001 = 10*11^4 + 3*11^3 + 4*11^2 + 114

Dividing 114 by 11 gives quotient 10 and remainder 4

So

151001 = 10*11^4 + 3*11^3 + 4*11^2 + 10*11 + 4

So v=10, w=3, x=4, y=10, z=4

is ONE solution. But is that the only one? We will
show that it indeed is the only solution:

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  (6 years ago)

In quest 11 s der not 7 n for 11 der exists only 1 solution

Is this solution Helpfull? Yes | No (1)  

Mohd Rashid  (6 years ago)

151001=62*7^7+6*7^3+1*7^2+0*7+32
v=62
w=6
x=1
y=0
z=32

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