Latest L&T Aptitude Question SOLUTION: A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink,

• Placement Papers
• /
• L&T
• /
• Numerical Ability
• /
• LCM and HCF

L&T Question Papers: L&T Company Profile

(#M40165824) L&T Numerical Ability question Keep an EYE

A drink vendor has 368 liters of Maaza, 80 liters of Pepsi and 144 liters of Sprite. He wants to pack them in cans, so that each can contains the same number of liters of a drink, and doesn't want to mix any two drinks in a can. What is the least number of cans required ?

Asked In L&T Devendra Marghade (5 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (1)   (0) Submit Your Solution LCM and HCF

Read Solution (1) :

Kumar  (5 years ago)

To find the least number of cans we need to find the HCF of 368, 80 and 144 which is 16.
368 = 2*2*2*2*23,
80 = 2*2*2*2*5
144*2*2*2*2*3*3
HCF = 2*2*2*2 = 16
Now least number of cans required = (368+80+144)/16 = 23+5+9 = 37.
Ans = 37 cans required of 16 litres each.

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.