Latest L&T Aptitude Question SOLUTION: A man buys 24 litres of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 10 litres of another mixture with 30% of liquid. What is the percentag

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A man buys 24 litres of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 10 litres of another mixture with 30% of liquid. What is the percentage of water in the new mixture?

Asked In L&T Devendra Marghade (5 years ago)

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K Pravalika  (5 years ago)

% of Liquid in Solution A = 25%

⇒ % of Water in Solution A = 75%

Volume of Solution A = 24 Litres

⇒ Volume of Water in Solution A = (75/100) × 24 = 18 Litres

% of Liquid in Solution B = 30%

⇒ % of Water in Solution A = 70%

Volume of Solution B = 10 Litres

⇒ Volume of Water in Solution B = (70/100) × 10 = 7 Litres

If Solution A is mixed with Solution B
⇒ Net Total Volume of Solution = (24 + 10) = 34 Ltrs

⇒ Net Total Volume of Water in Solution = (18+ 7) = 25Ltrs

% of Water in New Mixture = (Volume of Water in New Mixture / Volume of New Mixture) × 100

% of Water in New Mixture = (25 /34) × 100 = 73.52%

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