Latest tcs Aptitude Question SOLUTION: A game is played between 2 players and one player is declared as winner. All the winners from first round are played in second round. All the winners from second round are played in third round and so on. If 8 rounds are played to declare only one player as winner, how many players are played in first round? a) 256 b) 512 c) 64 d) 128

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(#M40001703) TCS aptitude question 2010 question Keep an EYE

A game is played between 2 players and one player is declared as winner. All the winners from first round are played in second round. All the winners from second round are played in third round and so on. If 8 rounds are played to declare only one player as winner, how many players are played in first round?
a) 256 b) 512 c) 64 d) 128

Asked In tcs Submited By-- UN (1 year ago)

Puzzle Status: Solved     By »» kannan

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kannan  (1 year ago)

8 rounds means 128-64-32-16-8-4-2-1
so 128matches were played in first round

teams= 128*2=
256

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(#M40000441) TCS MATHS PUZZLE No of players Keep an EYE

A game is played between 2 players and one player is declared as winner. All the winners from first round are played in second round. All the winners from second round are played in third round and so on. If 8 rounds are played to declare only one player as winner, how many players are played in first round?

Asked In TCS Submited By-- shamshuddin (2 year ago)

Puzzle Status: Solved     By »» venky

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venky   (2 year ago)

2^8=256 teams

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sandipan paul chowdhury  (2 year ago)

2^8=256

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skyspy5  (9 Month ago)

2^8=256 players

Is this solution Helpfull? Yes (4) | No (2)  

(#M40000954) TCS MATHS PUZZLE Keep an EYE

A game is played between 2 players and one player is declared as winner. All the winners from first round are played in second round. All the winners from second round are played in third round and so on. If 8 rounds are played to declare only one player as winner, how many players are played in first round?
a) 256 b) 512 c) 64 d) 128

Asked In tcs Submited By-- kumar abhishek (2 year ago)

Puzzle Status: Solved     By »» suchandra raavi

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suchandra raavi  (2 year ago)

ans: a (256)
Start from final round. For every round players double in a knockout game. So 8th round(final round)=2 players. Now 7th round double it=4 players. In that way calculate until 1st round. you get 256. or simply 2^n , n= no. of rounds. 2^8=256

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tk  (2 year ago)

last match(=8th) 2 players
2ndlast " (=7th) 2^2 "
3rdlst " (=6th) 2^3 "
. " (=5th) 2^4 "
. 2^5
. 2^6
. 2^7
finally(=1st) 2^8
=256 players

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Angshuman Bagchi  (2 year ago)

let x is the total no. of player played in 1st round.so x/2 player can play in 2nd round and x/4 for 3rd round & x/8 for next and by this way x/128 player can play for 8th round and after this round only 1 is winner.bcoz the game is played between 2 players & 1 is declared as winner & all winner is selected for next round.so only x/256 player can say as a winner after 8th round.so x/256 is equal to 1.x=256.so 256 will be the ans.

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smita dasgupta  (2 year ago)

2^8=256....if we divide 256/2....in dis way upto 8 times then we will get at the end only 2 players and finally 2/2=1 and only 1 will b winner..

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RAVI  (2 year ago)

2^8=256

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(#M40001079) TCS MATHS PUZZLE Keep an EYE

A game is played betwn 2 players and one player is declared as winner. all the winners from first round are played in second round.all the winners from second round are played in third round and so on.if 8 rounds are played to declare only one players as winner, how many players are played in first round?

Asked In TCS Submited By-- Ragini (2 year ago)

Puzzle Status: Unsolved

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RISHI KUMAR  (2 year ago)

8th round=2 players
7th round=2*2=4
6 =4*2=8
5 =8*2=16
4 =16*2=32
3 =32*2=64
2 =64*2=128
1 =128*2=256 players
for this type of problems try to solve from last round

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Somil Nain  (2 year ago)

2^8=256

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suchandra raavi  (2 year ago)

ans: 256
Start from final round. For every round players double in a knockout game. So 8th round(final round)=2 players. Now 7th round double it=4 players. In that way calculate until 1st round. you get 256. or simply 2^n , n= no. of rounds. 2^8=256

Is this solution Helpfull? Yes (5) | No   

Abhishek Adhikari  (2 year ago)

rounds players playing winner
8 2 1
7 4 2
6 8 4
5 16 8
4 32 16
3 64 32
2 128 64
1 256 128

so total number of players played in first round is 256

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sushil tripathi  (2 year ago)

at the starting the no. of player will be 2^8=256

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Ranvir Gupta  (2 year ago)

256->128->64->32->16->8->4->2

No of players is 256 in 1st round

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prakash  (2 year ago)

last round only 2 player
in second last " " 4=2^2 "
in 3rd last " " 8=2^3 "
.............................and so on
here total 8 round
hence 2^8 ans

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Amrit  (2 year ago)

256 player

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mahadev  (2 year ago)

sorry it's 256

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Shrishailam  (2 year ago)

Round No. of Players
8 1
7 2
6 4
5 8
4 16
3 32
2 64
1 128
answer=128

Is this solution Helpfull? Yes (2) | No (14)  

Vatan Kumar Seth  (2 year ago)

8th round would have been played by 2 players to declare 1 as winner;
which implies ,,in 7th round 4 players played to declare 2 as winners;
6th round=>8 players
...
.
.
1st round=>256 players
so the soluton is=>256

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mahadev  (2 year ago)

2^8/2 =128

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subhojit som  (2 year ago)

128

Is this solution Helpfull? Yes | No (13)