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(#M40017641) TCS Logical Reasoning question Keep an EYE

An equilateral triangle ABC with sides of length Θ cm is placed inside a square AXYZ with sides
of length 2*Θ cm so that side AB of triangle is along the base of the square (as shown).
The triangle is rotated clockwise about B, then C and so on along the sides of the square until the points
A, B and C return to their original positions. Find the length of the path (in cm) traversed by point C.

Asked In TCS tarun kapoor (11 years ago)

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anjul meid  (11 years ago)

7*pi*i
explaination : point C travels distance equal to arc of circle of radius 'i' with degrees of 120 and 30....and to re-reach their home position it takes 3 rounds of complete triangle along the sides of the given square so final equation becomes like this-----3*((3*(2*pi*i)/3)+(2*(2*pi*i)/12))

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anjul meid  (11 years ago)

angular displacement of point c :120,120,30,30,120 degree in a full round and after 3 full rounds point c will return to its original position and other 2 point also to their respective positions...do check it...and distance covered = 3*((2*pi*I)/3+(2*pi*I)/3+(2*pi*I)/12+(2*pi*I)/12+(2*pi*I)/3)=7*pi*I

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anjul meid  (11 years ago)

what are options???

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Riya Khanna  (11 years ago)

its not exact 7*pi*i bt close to 7*pi*1...
it wl take 3 full rounds n 5/9th part of a round more
do tell me the rght ans

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Shubhra Srivastva  (11 years ago)

can sb explain in detail??how u people r relating it wid circle??plz do explain it in a bit more ellaborative way..thnks in advance.

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