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Previous Question: Consider a number as follows..... 12345678910111213141516......37383940. This is nothing but numbers from 1 to 40 are written side by side to form a single number. Now what is the remainder when the number given above is divided by 36. Next Question: LET n!=1*2*3*4....*n for integer n>=1.if p=(1*1!)+(2*2!)+(3*3!)+......(10*10!),then p+2 when divided by 11! leaves a remainder as: 1. 10 2. 0 3. 7 4. 1

(#M40017951) SELF question What can be the values of letters ? Keep an EYE

abc+def=ghi: Devendra Marghade (11 years ago); Unsolved Read Solution (3); Is this Puzzle helpful? (0) (1) Submit Your Solution

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Previous Question: Consider a number as follows..... 12345678910111213141516......37383940. This is nothing but numbers from 1 to 40 are written side by side to form a single number. Now what is the remainder when the number given above is divided by 36. Next Question: LET n!=1*2*3*4....*n for integer n>=1.if p=(1*1!)+(2*2!)+(3*3!)+......(10*10!),then p+2 when divided by 11! leaves a remainder as: 1. 10 2. 0 3. 7 4. 1

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