Latest Elitmus Aptitude Question SOLUTION: find the number of possible value of X. for which (3*X+4)^2/(X+4)this gives the integer value. options a. 2 b.4 c. 6 d. infinite

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(#M40018109) ELITMUS question quant Keep an EYE

find the number of possible value of X.
for which (3*X+4)^2/(X+4)this gives the integer value.
options
a. 2 b.4 c. 6 d. infinite

Asked In Elitmus Deepak kumar Dubey (11 years ago)

Unsolved Read Solution (7)

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Sangeeta  (11 years ago)

6 values are possible.
(3*X+4)^2/(X+4)
= (2X+X+4)^2/(X+4)

For integer value of (3*X+4)^2/(X+4)
(2X)^2/(X+4) should be integer .
For that (2X+8-8)^2)/(X+4) should be integer or 8^2/(X+4) should be integer.
which is possible with 6 values of X like -2, 0,4,12,28,60.
like X=0,4,12, 28,60

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Raman  (11 years ago)

@ Shresth,

Pls check the

u hv solved it as
(3*X+4)^[2/(X+4)]
I think,it should be solved as
[(3*X+4)^2]/(X+4)

If we consider
(3*X+4)^[2/(X+4)], then x=0 also gives desired result as
(3*0+4)^[2/(0+4)] = 4^(1/2)=2 which is integer.
(3*X+4)^2/(X+4)

Is this solution Helpfull? Yes (6) | No (1)  

jaspreet  (10 years ago)

6 should be the ans. 3x+7 when divided by x+4 gives negative remainder 5.So,when (3x+7)^2 is divided,remainder net is 25.so,basically prob reduces to intg. values of x for which 25/X+4 gives 0 remainder.Clearly the values are (-29,-9,-5,-3,1,21).

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SHRESTH  (11 years ago)

if x=4, then
(3*4+4=16)
and
2/(4+4)=1/4
now
16^1/4 =4 which is integer.
Except 4 , all are giving results in under roots which are not integer.

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shweta sharma  (11 years ago)

wht is d rght ans?

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ashes  (10 years ago)

14 values are possible x=-3,-5,60,-68,-2,-6,-8,0,4,-12,12,-20,28,-36

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Amitkumar  (8 years ago)

ans infinite

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