Latest Elitmus Aptitude Question SOLUTION: there are three players playing a chess competetion at a time only 2 players can play the game and player A wins 15 games player B wins 14 games player C wins 9 games so who played

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(#M40018404) ELITMUS question Keep an EYE

there are three players playing a chess competetion at a time only 2 players can play the game and player A wins 15 games player B wins 14 games player C wins 9 games so who played the 11th match and how many games did player C lost

Asked In Elitmus mithlesh dhore (11 years ago)

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Sumit Rawal  (11 years ago)

by the way sahil has done 11th match is between A nd B and C has lost total 15 matches since first 9 were won by C
10th match A beats C
11th match A nd B
12th match A/B with C (C lost)
13th match A and B
14th match A/b with C ( Clost )
16th A/b with C ( C lost)
In this way among first 11 matches C lost 1 and in rest of 27 matches mathes lost by C 38-12/2 +2=13+1=14
hence total no matches lost by C =14 +1=15

Is this solution Helpfull? Yes (15) | No (2)  

ranjeet singh chauhan  (10 years ago)

This question can not be answered.....As the data given is not sufficient...

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Mallisetty Srinivasulu  (11 years ago)

The 11 th match is between B and C.C lost 16 matches

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farjana sayyed  (10 years ago)

how could we tell that particular match held between 2 parties?
could you give some more clarification sumit?

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shir  (11 years ago)

xplain this one plz.....

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Sahil Jain  (11 years ago)

Since there is a difference of
1 win between A and B therefore, A has won 1 game more than B.
6 win between A and C therefore, A has won 6 games more than C and,
5 win between B and C therefore, B has won 5 games more than C.

Total no. of games played (considering no match resulted in a draw)=> 15+14+9=38

Since, C has to won 9 games and A has won 1 game more than B...
Therefore, 11th game has to played between A and B in any case.
No. of games C has lost->1.

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Rachit Pande  (10 years ago)

try this
as each match will be won by someone hence total matches played =(15+14+9) = 38
As two players play a match hence each player played 38/2 =19 matches
hence C has lost (19-9)= 10 matches

As for part on it cannot be determined as we don't have any information about the sequence of the matches

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babu rao ganpat rao apte  (10 years ago)

this cant be predicted yaar...suppose starting 9 matches were btw a and b.... what now any of three can play the next 4 or 5 matches...how can u prdict that

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naga sarath chand  (10 years ago)

small part of the question not added is,
the winner of a particular game will play with the other player that is 3rd player,and this is same for all the games they played.

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naga sarath chand  (10 years ago)

one more error in the question is, A played 15 games but not won 15 games,
B played 14 games not won 14 games and C played 9 games,not won 4 games.

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ARPIT SRIVASTAVA  (10 years ago)

Some more explanations required...

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