Latest Elitmus Aptitude Question SOLUTION: 5 boxes are there viz. 1,2,3,4,5. We have blue balls and red balls. What is the probability of filling the boxes with no two consecutive blue balls?

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(#M40018620) ELITMUS Numerical Ability question Keep an EYE

5 boxes are there viz. 1,2,3,4,5. We have blue balls and red balls. What is the probability of filling the boxes with no two consecutive blue balls?

Asked In Elitmus (10 years ago)

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anjul meid  (10 years ago)

3/8

cases with consecutive blue balls can be categorised as:-
1)2 consecutive blue balls i.e BB => total cases with BB= 12
2)3 consecutive blue balls i.e BBB => total cases with BBB=5
3)4 consecutive blue balls i.e BBBB => total cases with BBBB=2
4)5 consecutive blue balls i.e BBBBB => total cases with BBBBB=1
total cases with consecutive blue balls =20;
so total case with no consecutive blue balls = 32-20=12
p=12/32=3/8

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vinod  (10 years ago)

edit:

there are two possibilities so= 2/32
= 1/16

Is this solution Helpfull? Yes (13) | No (3)  

Anusha  (10 years ago)

There are 13 cases in which 2 blue balls will not recur consecutively:
5 red => 1 case
4 red + 1 blue => (5!)/(4!) => 5 cases [BRRRR,RBRRR,RRBRR,RRRBR,RRRRB]
3 red + 2 blue => [(5!)/(3! 2!)] - [4!/3!] => 6 cases
2 red + 3 blue => 1 case [BRBRB]
total fav cases = 13
sample space = 2^5 = 32
probability = 13/32

Is this solution Helpfull? Yes (12) | No (2)  

ankita  (10 years ago)

we have 5 boxes thus total possible outcomes are 2*2*2*2*2=32,and favourable outcomes include 2*1*1*1*1=2,thus probability = 1/16

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vinod  (10 years ago)

we can fill up in two ways i.e
1) R B R B R
2) B R B R B these are two favorable cases
and we have many red and blue balls, so each box has two choices either red or blue so, 2*2*2*2*2=32 ways are possible generally

therefore probability= 1/32

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siddhant  (10 years ago)

ans is 13/32..........

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sushmita nigam  (10 years ago)

1/16 is the correct soln.. is it????

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anjul meid  (10 years ago)

@ankita and vinod : YOU HAVE LEAVED CASES LIKE RRRRR,RRRRB,BRRRR,RBRRR,BRRRB,AND MANY MORE

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Prakash  (10 years ago)

please elaborate the answer.....

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mohan  (10 years ago)

4/5 bcoz in d problm stated that no two balls can be blue so, imagine two blue ball as one unit now it bcom units to fill it can be done in 4c3 ways i.e 4, now in remaning 3 can befilled with 3! ways i.e 6 .. so now boxes with two concequitive blue become 6*4=24... so now subtract these from total number of ways i.e total number of ways in which we can fill is 5! i.e 120 then we will get 96 so now probability bcomes 96/120=4/5

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Agniv Chatterjee  (8 years ago)

@Anjul Bro please tell how did u get please once more clarify your answer :)

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